小编Cha*_*der的帖子

我需要在空格上拆分一个字符串,但我需要忽略一些包含空格的复合关键字.例如,我有一个String如下,

String testCase = "The patient is currently being treated for Diabetes with Thiazide diuretics";

我需要拆分字符串,但需要Thiazide diuretics作为一个整体复合表达式

String[] array = testCase.split(" ");

结果必须如下:

The
patient
is
currently
being
treated
for
Diabetes
with 
Thiazide diuretics

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怎么做 ？

我有一个私有方法，可用于使用RegEx查找药物名称。代码如下

private boolean containsExactDrugName(String testString, String drugName) {

    int begin = -1;
    int end = -1;

    Matcher m = Pattern.compile("\\b(?:" + drugName + ")\\b|\\S+", Pattern.CASE_INSENSITIVE | Pattern.UNICODE_CASE).matcher(testString);
    ArrayList<String> results = new ArrayList<>();

    while (m.find()) {
        results.add(m.group());
    }

    boolean found = results.contains(drugName);
    return found;
}

它应该带有药物名称，并在文本String中找到完全匹配的内容。这意味着，如果药物名称为，insuline并且字符串文本为The patient is taking insulineee for the treatment of diabetes，则它将中断。它需要的完全匹配The patient is taking insuline for the treatment of diabetes。

但是，我还需要区分大小写的匹配项，如果文本为The patient is taking Insuline for the treatment of diabetes …