我目前在碰撞语句中有这个代码,如果与对象发生碰撞,那么这个粒子会发生,但我该怎么做呢?因为它永远持续下去,而我只希望每次接触发生几次
SKEmitterNode *emitter = [NSKeyedUnarchiver unarchiveObjectWithFile:[[NSBundle mainBundle] pathForResource:@"ff" ofType:@"sks"]];
emitter.zPosition = 0;
emitter.particlePositionRange = CGVectorMake(0, self.size.height);
emitter.position = CGPointMake(self.size.width, self.size.height/2);
[self addChild:emitter];
Run Code Online (Sandbox Code Playgroud) 我有一个delete.php带有是/否按钮的文件调用deleteRecord.php从数据库中删除所选行.
问题似乎是我没有将pass的变量传递ProjectID给deleteRecord文件.
有人可以告诉我有什么问题吗?
delete.php
<?php
error_reporting(E_ALL|E_STRICT); ini_set('display_errors', true);
require('includes/conn.inc.php');
require('includes/functions.inc.php');
$sProjectID = safeInt($_GET['ProjectID']);
$stmt = $mysqli->prepare("SELECT ProjectID, ProjectName, ProjectImage, LanguageUsed, ApplicationUsed, Description FROM Projects WHERE ProjectID = ?");
$stmt->bind_param('i', $sProjectID);
$stmt->execute();
$stmt->bind_result($ProjectID, $ProjectName, $ProjectImage, $LanguageUsed, $ApplicationUsed, $Description);
$stmt->fetch();
$stmt->close();
?>
<!DOCTYPE HTML>
<input name="ProjectID" type="hidden" value="<?php echo
$ProjectID; ?>">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>Delete <?php echo $ProjectName; ?></title>
<link href="styles/cms.css" rel="stylesheet" type="text/css">
</head>
<body>
<div id="container">
<header>
<h1>Delete …Run Code Online (Sandbox Code Playgroud)