我有一个SQL数据库,我想使用phplyadmin导入,但我收到此错误.
CREATE TABLE `wp_commentmeta` (
`meta_id` BIGINT( 20 ) UNSIGNED NOT NULL AUTO_INCREMENT ,
`comment_id` BIGINT( 20 ) UNSIGNED NOT NULL DEFAULT '0',
`meta_key` VARCHAR( 255 ) DEFAULT NULL ,
`meta_value` LONGTEXT,
PRIMARY KEY ( `meta_id` ) ,
KEY `comment_id` ( `comment_id` ) ,
KEY `meta_key` ( `meta_key` ( 191 ) )
) ENGINE = Aria AUTO_INCREMENT =3843 DEFAULT CHARSET = utf8
PAGE_CHECKSUM =1 DELAY_KEY_WRITE =1 TRANSACTIONAL =1;
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MySQL说:文档
#1064 - 您的SQL语法有错误; 检查与MySQL服务器版本对应的手册,以便在第9行的"PAGE_CHECKSUM = 1 DELAY_KEY_WRITE = 1 TRANSACTIONAL = …
我收到以下错误
线程"main"中的异常javax.persistence.PersistenceException:[PersistenceUnit:person]无法在org.hibernate.jpa的org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.persistenceException(EntityManagerFactoryBuilderImpl.java:1249)中构建Hibernate SessionFactory.在org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl $ 4的org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl $ 4.perform(EntityManagerFactoryBuilderImpl.java:860)中的boot.internal.EntityManagerFactoryBuilderImpl.access $ 600(EntityManagerFactoryBuilderImpl.java:120) .perform(EntityManagerFactoryBuilderImpl.java:850)位于org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.build(EntityManagerFactoryBuilderImpl.java)的org.hibernate.boot.registry.classloading.internal.ClassLoaderServiceImpl.withTccl(ClassLoaderServiceImpl.java:425) :849)org.hibernate.ogm.jpa.Hibe上的org.hibernate.jpa.HibernatePersistenceProvider.createEntityManagerFactory(HibernatePersistenceProvider.java:75)rnateOgmPersistence.createEntityManagerFactory(HibernateOgmPersistence.java:63)位于javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:55)的javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:39)at com.ihappyk.utility.Utility.setUpEntityManagerFactory (utility.java:11)com.ihappyk.work.PersonWorker.main(PersonWorker.java:14)引起:org.hibernate.MappingException:无法实例化id生成器[entity-name = com.ihappyk.model.Person ] org.hibernate.id.factory.内部.DefaultIdentifierGeneratorFactory.createIdentifierGenerator(DefaultIdentifierGeneratorFactory.java:123)位于org.hibernate.internal.SessionFactoryImpl的org.hibernate.mapping.SimpleValue.createIdentifierGenerator(SimpleValue.java:225).(SessionFactoryImpl .java:323)org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1859)org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl $ 4.perform(EntityManagerFactoryBuilderImpl.java:857)... 9 m ore造成:org.hibernate.HibernateException:org.hibernate.id.factory.internal中org.hibernate.id.UUIDGenerator.configure(UUIDGenerator.java:111)上UUID转换的意外返回类型[java.lang.Long] .DefaultIdentifierGeneratorFactory.createIdentifierGenerator(DefaultIdentifierGeneratorFactory.java:117)... 13更多
Utilty.java
public class Utility {
private static EntityManagerFactory entityManagerFactory;
//@BeforeClass
public static EntityManagerFactory setUpEntityManagerFactory() {
entityManagerFactory = Persistence.createEntityManagerFactory( "person" );
return entityManagerFactory;
}
//@AfterClass
public static void closeEntityManagerFactory() {
entityManagerFactory.close();
}
}
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持久的阶级
@Entity
public class Person {
@Id
@GeneratedValue(generator = "uuid")
@GenericGenerator(name = "uuid", strategy = "uuid2")
private long id;
private String firstName;
private …Run Code Online (Sandbox Code Playgroud) session_id($randomString)和之间的明显区别是session_regenerate_id()什么?两者似乎都更改了会话ID:
session_regenerate_id()将用一个新的ID替换当前的会话ID,并保留当前的会话信息。
session_id()用于获取或设置当前会话的会话ID。
如果我做对了,session_regenerate_id()创建一个新的会话文件并复制数据,并带有删除旧文件的选项。同时session_id($randomString)只需更改现有文件中的会话ID。
如果是这样,复制文件有什么好处?从防止会话固定的角度来看,如何更好?
这个答案,或者我找到的任何其他答案,都无法回答我的问题。
我从 3 天开始就面临问题。我需要将 EditText 中的文本保存到 SharedPreferences 中。用户使用指纹扫描仪进行身份验证后,应将此文本加密保存在 SharedPreference 中。然后我需要解密这些数据,所以我需要一个永久存储机制来生成 SecretKey。
private SecretKey createKey(String keyName) throws NoSuchAlgorithmException, NoSuchProviderException, InvalidAlgorithmParameterException {
KeyGenerator keyGenerator = KeyGenerator.getInstance(KeyProperties.KEY_ALGORITHM_AES, ANDROID_KEY_STORE);
keyGenerator.init(new KeyGenParameterSpec.Builder(keyName,
KeyProperties.PURPOSE_ENCRYPT | KeyProperties.PURPOSE_DECRYPT)
.setKeySize(DEFAULT_KEY_SIZE)
.setBlockModes(KeyProperties.BLOCK_MODE_CBC)
.setUserAuthenticationRequired(true)
.setEncryptionPaddings(KeyProperties.ENCRYPTION_PADDING_PKCS7)
.build());
return keyGenerator.generateKey();
}
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当我尝试KeyStore使用FileInputStream以下方法从文件加载时发生问题:
public static SecretKey getKeyFromKeystore(Context context) throws KeyStoreException, IOException, CertificateException, NoSuchAlgorithmException {
FileInputStream fis = null;
try {
fis = context.openFileInput(KEYSTORE_FILENAME);
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
KeyStore keyStore = KeyStore.getInstance("AndroidKeyStore");
// FileInputStream …Run Code Online (Sandbox Code Playgroud) 我正在尝试在对话框上添加回收站视图,但对话框未显示任何内容...我已在回收站视图上添加卡片,并想在对话框上显示回收站视图
android.support.v7.app.AlertDialog.Builder dialog = new android.support.v7.app.AlertDialog.Builder(getContext());
LayoutInflater inflater = (LayoutInflater) getContext().getSystemService(Context.LAYOUT_INFLATER_SERVICE);
View dialogView = inflater.inflate(R.layout.last_transaction_report, null);
recyclerView = (RecyclerView) dialogView.findViewById(R.id.transactio_rep_recyclerView);
dialog.setView(dialogView);
AlertDialog alertDialog = dialog.create();
// alertDialog.setContentView(dialogView);
alertDialog.show();
adapter = new TransactionReportCardAdapter(listTransactionDetails, this);
recyclerView.setAdapter(adapter);
Run Code Online (Sandbox Code Playgroud) 我试图在ArrayList中进行二进制搜索,但binarySearch方法不适用于Long,以及Double和Float.我的代码是
import java.util.*;
public class BinarySearchInArrayList
{
public static void main(String[]args)
{
ArrayList<Long> ar = new ArrayList();
for(long l = 1;l<100000;l++)
{
ar.add(l);
}
System.out.println("arraylist: "+ar);
System.out.println("Which number's index do you want to know? ");
Scanner scan = new Scanner(System.in);
int p = scan.nextInt();
int index = Collections.binarySearch(ar,p);
System.out.println("number "+p+" has index "+index);
}
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当我使用Integer而不是Long,它工作正常,但我想用它Long.你能帮我吗?
我是初学者,我在这段代码中提出了一个HTTP请求并得到了回复:
public void postData() {
// Create a new HttpClient and Post Header
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://192.168.1.105/moodle/login/index.php"); //http://192.168.1.105/moodle/login/index.php
try {
// Add your data
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
nameValuePairs.add(new BasicNameValuePair("username", "admin"));
nameValuePairs.add(new BasicNameValuePair("password", "dtkTj29000g!"));
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
httppost.setHeader("Content-Type","application/x-www-form-urlencoded;charset=UTF-8");
// Execute HTTP Post Request
HttpResponse response = httpclient.execute(httppost);
String responseContent = EntityUtils.toString(response.getEntity());
Log.i("Response", responseContent );
Header[] header=response.getAllHeaders();
for(int i=0;i<header.length;i++){
String a=header[i].getValue();
String b=header[i].getName();
Log.i("quangggggggggggggg",b+"__________"+a);
}
WebView webview = (WebView)findViewById(R.id.webkit1);
webview.loadDataWithBaseURL(null,responseContent, "text/html", "utf-8",null);
/* cookies = …Run Code Online (Sandbox Code Playgroud) 我编写了一个函数来处理异步函数引发的异常,例如:
protected safeAsync(f : e.RequestHandler) : e.RequestHandler {
/* how to detect if `f` is an async function here ?? */
const binded = f.bind(this);
return async function innerCall(req : e.Request, res : e.Response, next : Function) {
try {
return await binded(req, res, next);
} catch (err) {
log.debug(err);
return next(err);
}
}
}
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该参数f应该是一个异步函数,例如
public async signupPost(req : e.Request, res : e.Response, next : Function) {/*...*/}
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我的问题是:
在 中safeAsync,有没有办法检测是否f是异步函数,以便我可以记录对 的意外调用safeAsync?
我正在尝试更新 MySQL 数据库中的存储函数。更新将发布到多个设备,因此我通过 update.sql 文件进行更新。
这是函数
DROP FUNCTION `STAFF_MPT`;
CREATE DEFINER=`jelena`@`%` FUNCTION `STAFF_MPT`(`par_stocktake_staff_id` INT) RETURNS DECIMAL(20,0) NOT DETERMINISTIC CONTAINS SQL SQL SECURITY DEFINER BEGIN
DECLARE proc_total INT;
DECLARE proc_time INT;
SET proc_total = (SELECT SUM(quantity) FROM stocktake_scans WHERE stocktake_staff_id = par_stocktake_staff_id);
SET proc_time = (SELECT TIMESTAMPDIFF( SECOND , MIN( scan_date ) , MAX( scan_date ) ) AS area_time
FROM stocktake_scans
WHERE stocktake_staff_id = par_stocktake_staff_id
);
RETURN (proc_total/proc_time)*3600;
END
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刚才测试组给我报告说使用这个功能的报告没有正常生成。我尝试在 PMA SQL 查询窗口中运行代码并得到以下结果:
You have an error in your SQL syntax; …Run Code Online (Sandbox Code Playgroud) 我有一个代码,请参见下面。该时间的时区16:17是Europe/Vilnius。我的目标是应用时区$tz2 = 'Africa/Dakar'并获取时区16:17时间Africa/Dakar。
$tz1 = 'Europe/Vilnius';
$tz2 = 'Africa/Dakar';
$a='16';
$b='17';
$match_time = date("H:i", strtotime($a.":".$b));
$dt1 = new DateTime($match_time, $tz1);
$dt2 = new DateTime($match_time, $tz2);
echo "match date".$match_time;
echo "dt1".$dt1;
echo "dt2".$dt2;
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我尝试了很多方法来做到这一点。现在这段代码给了我一个错误:
致命错误未捕获错误:在 /home4/phptest/public_html/code.php70(5) 中的字符串上调用成员函数 format() :eval()'d 代码:8 堆栈跟踪:#0 /home4/phptest/public_html/ code.php70(5): eval() #1 {main} 在第 8 行抛出
我的问题是如何修复代码以获得结果,这是进行此类转换的便捷方法吗?
我正在尝试破译Dockerfile的以下行:
ADD MyApplication.jar app.jar
RUN (cd app.jar/MyApplication;tar -cf - src) | (cd ../..;tar -xf -) \
&& (cd app.jar/MyApplication;tar -cf - opt/att/ajsc/lib) | (cd ../..;tar -xf -) \
&& (cd app.jar/MyApplication;tar -cf - opt/att/ajsc/config) | (cd ../..;tar -xf -)
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我认为它只是试图将一个jar文件解压缩到Docker镜像中的特定目录中,但是我想确定.
我尝试遵循: PHP警告:PHP启动:无法加载动态库'mcrypt.so'
sudo apt-get -y install gcc make autoconf libc-dev pkg-config
sudo apt-get -y install php7.2-dev
sudo apt-get -y install libmcrypt-dev
sudo pecl install mcrypt-1.0.1
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我得到:
pecl/mcrypt requires PHP (version >= 7.2.0, version <= 7.3.0, excluded versions: 7.3.0), installed version is 7.3.3-1+ubuntu14.04.1+deb.sury.org+1
No valid packages found
install failed
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我使用需要的prestashop
我有一个看起来像这样的功能:
function eco($a, $c, $d, $e, $g) {
$f= (($a/$c)/ $d)*$e;
$h=$f/$g;
}
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当我调用此函数并回显结果时,不会显示任何内容
$ok = eco(9,9,9,89,89);
echo $ok;
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实际上,我需要$h进一步计算的值,但我无法检索它.如何显示值$h?