小编Joh*_*nny的帖子

我有以下代码,你可以看到后台工作程序搜索文件,并且在进度中更改了事件文件被添加到listview,但是由于有很多文件被添加到listview,UI变得没有响应,我可以睡在循环中的线程,但我不认为这是一个很好的做法,什么是防止UI冻结的最佳方法？

为了详细说明,listview是表单上的表单控件.

void bg_DoWork(object sender, DoWorkEventArgs e)
{
    Stack<string> dirs = new Stack<string>(20);
    dirs.Push(e.Argument.ToString());
    while (dirs.Count > 0)
    {
        string currentDir = dirs.Pop();
        string[] subDirs;
        try { subDirs = System.IO.Directory.GetDirectories(currentDir); }
        catch (UnauthorizedAccessException) { continue; }
        catch (System.IO.DirectoryNotFoundException) { continue; }

        string[] files = null;
        try { files = System.IO.Directory.GetFiles(currentDir); }

        catch (UnauthorizedAccessException) { continue; }
        catch (System.IO.DirectoryNotFoundException) { continue; }
        foreach (var file in files) { bg.ReportProgress(0, file); }
        foreach (string str in subDirs) { dirs.Push(str); }
    }
} …

为什么我不能通过它的接口(ItestClass)访问基类(testClass)属性？我创建了接口以避免实际的Control(winforms/wpf)属性在第三个类(newClass)中可见.如果那不可能有更好的方法吗？

public class testClass : Control, ItestClass
{
    public int Property1 { set; get; }
    public int Property2 { set; get; }
    public testClass() { }
}
public interface ItestClass
{
    int Property1 { get; set; }
    int Property2 { get; set; }
}

public class newClass : ItestClass
{
    public newClass()
    {
        // Why are the following statements are not possible?
        Property1 = 1;
        // OR
        this.Property1 = 1;
    }
}

使长话短说.我有以下代码:

class MyList : IEnumerable
{
    private List<string> T1 = new List<string>();
    private List<string> T2 = new List<string>();
    private List<string> T3 = new List<string>();
    public List<string> Name { set { T1 = value; } get { return T1; } }
    public List<string> DataType { set { T2 = value; } get { return T2; } }
    public List<string> Nullable { set { T3 = value; } get { return T3; } }
    IEnumerator IEnumerable.GetEnumerator()
    {
        return (IEnumerator)GetEnumerator();
    }
    public MyList<List<string>, …