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在类路径资源[jpaContext.xml]中定义名称为'entityManagerFactory'的bean时出错

我有一个春天的问题,我是一个新手使用这个框架与Hibernate,JPA和Maven,我正在关注pluralsight的教程但是当在服务器中启动应用程序时,我有这个错误消息.

Grave: Context initialization failed
org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'entityManagerFactory' defined in class path resource [jpaContext.xml]: Cannot resolve reference to bean 'dataSource' while setting bean property 'dataSource'; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'dataSource' defined in class path resource [jpaContext.xml]: Error setting property values; nested exception is org.springframework.beans.PropertyBatchUpdateException; nested PropertyAccessExceptions (1) are:
PropertyAccessException 1: org.springframework.beans.MethodInvocationException: Property 'driverClassName' threw exception; nested exception is java.lang.IllegalStateException: Could not load JDBC driver class [com.postgresql.driver]
    at org.springframework.beans.factory.support.BeanDefinitionValueResolver.resolveReference(BeanDefinitionValueResolver.java:329)
    at org.springframework.beans.factory.support.BeanDefinitionValueResolver.resolveValueIfNecessary(BeanDefinitionValueResolver.java:107)
    at …
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java xml spring hibernate maven

5
推荐指数
1
解决办法
5万
查看次数

应用程序(应用程序侦听器)的类配置的错误信息org.springframework.web.context.ContextLoaderListner

我在春季遇到问题,我是与Hibernate,JPA和Maven一起使用此框架的新手,我正在遵循有关复数视力的教程,但是在服务器中启动应用程序时出现此错误消息

Grave: Erreur lors de la configuration de la classe d'écoute de l'application (application listener) org.springframework.web.context.ContextLoaderListner
    java.lang.ClassNotFoundException: org.springframework.web.context.ContextLoaderListner
        at org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1702)
        at org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1547)
        at org.apache.catalina.core.DefaultInstanceManager.loadClass(DefaultInstanceManager.java:532)
        at org.apache.catalina.core.DefaultInstanceManager.loadClassMaybePrivileged(DefaultInstanceManager.java:514)
        at org.apache.catalina.core.DefaultInstanceManager.newInstance(DefaultInstanceManager.java:142)
        at org.apache.catalina.core.StandardContext.listenerStart(StandardContext.java:4876)
        at org.apache.catalina.core.StandardContext.startInternal(StandardContext.java:5455)
        at org.apache.catalina.util.LifecycleBase.start(LifecycleBase.java:150)
        at org.apache.catalina.core.ContainerBase$StartChild.call(ContainerBase.java:1559)
        at org.apache.catalina.core.ContainerBase$StartChild.call(ContainerBase.java:1549)
        at java.util.concurrent.FutureTask.run(FutureTask.java:262)
        at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1145)
        at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:615)
        at java.lang.Thread.run(Thread.java:744)

   févr. 11, 2014 10:49:15 AM org.apache.catalina.core.StandardContext listenerStart 
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这是我的“ web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
    <context-param>

    <param-name>contextConfigLocation </param-name>
    <param-value>classpath:/jpaContext.xml</param-value>

    </context-param>

    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListner</listener-class>
    </listener>
    <servlet>
        <servlet-name>fitTrackerServlet</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>/WEB-INF/config/servlet-config.xml, /WEB-INF/config/jpaContext.xml</param-value> …
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java spring hibernate jpa maven

0
推荐指数
1
解决办法
8191
查看次数

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