小编use*_*108的帖子

在这里,我正在尝试使用search api 1.1检索包含标签'V57'的推文.通过使用,倾倒和看到搜索词的结果,

$search_tim = $connection->get('search/tweets',array('q' => ' #V57', 'count' => 5, 'result_type' => 'recent'));

这是执行var_dump后的结果:

object(stdClass)#10 (2) {
["statuses"]=>
 array(5) {
[0]=>
object(stdClass)#11 (25) {
  ["metadata"]=>
  object(stdClass)#12 (2) {
    ["result_type"]=>
    string(6) "recent"
    ["iso_language_code"]=>
    string(2) "en"
  }
  ["created_at"]=>
  string(30) "Wed Feb 12 16:26:35 +0000 2014"
  ["id"]=>
  float(4.33638273555E+17)
  ["id_str"]=>
  string(18) "4336382731354561"
  ["text"]=>
  string(131) "RT @useracc: Plz consult a doctor #V57"
  ["source"]=>
  string(84) "Twitter for Android"
  ["truncated"]=>
  bool(false)
  ["in_reply_to_status_id"]=>
  NULL
  ["in_reply_to_status_id_str"]=>
  NULL
  ["in_reply_to_user_id"]=>
  NULL
  ["in_reply_to_user_id_str"]=>
  NULL
  ["in_reply_to_screen_name"]=>
  NULL
  ["user"]=>
  object(stdClass)#13 …

目前我有一个RecyclerView包含一些项目列表.我正在听Scroll listenerRecyclerView,如果RecyclerView在某个时候说500,它应该隐藏工具栏,当它超过500+时它应该保持隐藏状态.同样,当我达到<= 450时,它会显示工具栏.

这是我到目前为止尝试过的代码.问题是,

1. 它隐藏了工具栏,但它隐藏或显示在上述点时闪烁.

2. 如何实现平滑的工具栏隐藏？

   recyclerView.addOnScrollListener(new RecyclerView.OnScrollListener() {
           @Override
           public void onScrollStateChanged(RecyclerView recyclerView, int newState) {
               super.onScrollStateChanged(recyclerView, newState);
   
   
           }
   
   
           @Override
           public void onScrolled(RecyclerView recyclerView, int dx, int dy) {
               super.onScrolled(recyclerView, dx, dy);
   
               scrollD = scrollD + dy;
               Log.d("key", "DY is .." + (dy + scrollD));
   
               if (scrollD >= 500) {
                 // code to hide
               }
   
               if (scrollD <= 450) {
   
   
                // code to show
   
               }
           }
       });
   

   Run Code Online (Sandbox Code Playgroud)

我正在尝试使用新的Recycler View列出数据.我已经按照本教程,现在面临着一个问题.

这是我的

MainActivity.java

package com.example.i.newworkspace;

import android.os.Bundle;
import android.support.v7.app.ActionBarActivity;
import android.support.v7.widget.LinearLayoutManager;
import android.support.v7.widget.RecyclerView;
import android.view.LayoutInflater;
import android.view.Menu;
import android.view.MenuItem;
import android.view.View;
import android.view.ViewGroup;
import android.widget.TextView;


public class MainActivity extends ActionBarActivity {

TextView tv;
RecyclerView recyclerView;
RecyclerView.Adapter mAdapter;
String[] myDataset = {"One","Two","Three","Four","Five"};

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    recyclerView = (RecyclerView) findViewById(R.id.recyclerview);
    recyclerView.setLayoutManager(new LinearLayoutManager(this));
    recyclerView.setHasFixedSize(true);
    mAdapter = new MyAdapter(myDataset);
    recyclerView.setAdapter(mAdapter);

}


@Override
public boolean onCreateOptionsMenu(Menu menu) {
    // Inflate the menu; this adds items to the …

我有一个listView,最初有一些内容.如果获得相同的内容,我删除了重复linkedhashset.现在,我想复制linkedhashset内容,即没有重复内容到新ArrayList.

我试图通过复制

p.addAll(0,lhm);  // P is the instance of  ArrayList and lhm is linkedHashset instance

但是,也ArrayList包括复制内容.

示例:

 ArrayList<Price> p = new ArrayList<Price>();

     p.add(new Price("Banana", 60));
     p.add(new Price("Apple", 80));

    LinkedHashSet<Price> lhm = new LinkedHashSet<Price>(p); 
    lhm.add(new Price("Banana", 20)); 
    lhm.add(new Price("Apple", 40));
    lhm.add(new Price("Orange", 30)); 
    for(Price pr:lhm)
    {
        System.out.println(pr);
    } 
    Price duplicate = new Price("Banana", 20);
    System.out.println("inserting duplicate object..."); 
    lhm.add(duplicate);
    lhm.add(new Price("Apple", 40));
    p.addAll(0,lhm);
    System.out.println("After insertion:"); 
    for(Price pr:lhm)
    {
        System.out.println(pr);
    }

    for (int i = …

MainActivity.class

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    DatabaseHandler db = new DatabaseHandler(this);

    // Inserting Users
    Log.d("Insert: ", "Inserting ..");
    db.addContact(new Contact("Ravi", "kumar", 1, getDateTime()));
}

 public String getDateTime() {
    SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss", Locale.getDefault());
    Date date = new Date();
    return simpleDateFormat.format(date);
}

DatabaseHandler.class

public class DatabaseHandler extends SQLiteOpenHelper {


    Context context;
    private static final int DATABASE_VERSION = 1;
    private static final String DATABASE_NAME = "dbname";
    private static final String TABLE_USERS = "users";

    private static final String …

我有一个场景,用户在搜索框中输入一个字符串.如果输入的字符串到达​​多个单词,我会使用,

$text = "Hello World";
$pieces = explode(' ', $text);

我将获得第一个和第二个任期

$pieces['0'] & $pieces['1'].

但是,如果用户键入类似的内容,

$text = "Hello                    World";

我应该如何获得第二个学期？

如果我var_dump的结果,我得到了

array(12) {
  [0]=>
  string(5) "Hello"
  [1]=>
  string(0) ""
  [2]=>
  string(0) ""
  [3]=>
  string(0) ""
  [4]=>
  string(0) ""
  [5]=>
  string(0) ""
  [6]=>
  string(0) ""
  [7]=>
  string(0) ""
  [8]=>
  string(0) ""
  [9]=>
  string(0) ""
  [10]=>
  string(0) ""
  [11]=>
  string(5) "World"
}