小编use*_*337的帖子

如何在JSP中使用twitter bootstrap

我无法理解为什么我的jsp页面不会破解引导程序样式.

我的hello.jsp

<%@ taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core" %>
<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="utf-8">
    <meta http-equiv="X-UA-Compatible" content="IE=edge">
    <meta name="viewport" content="width=device-width, initial-scale=1">
    <title>Bootstrap 101 Template</title>
    <link href="<c:url value="/bootstrap/css/bootstrap.min.css"/>" rel="stylesheet">
</head>
<body>
<h1>Hello, world!</h1>

<div class="btn-group">
    <button type="button" class="btn btn-default">Left</button>
    <button type="button" class="btn btn-default">Middle</button>
    <button type="button" class="btn btn-default">Right</button>
</div>

<script src="<c:url value="/bootstrap/js/bootstrap.min.js"/>"></script>
</body>
</html>

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我的目录项目结构:

在此输入图像描述

任何想法如何正确添加引导程序？

html css jsp twitter-bootstrap

use*_*337

2014 03-07

8
推荐指数

1
解决办法

4万
查看次数

为什么我的自定义PermissionEvaluator不起作用？

我无法理解为什么我的安全性无法正常工作.方法hasPermission()在Evaluator类中甚至没有被调用.我认为我的安全配置有问题.

我的安全配置:

<?xml version="1.0" encoding="UTF-8"?>
<bean:beans xmlns:bean="http://www.springframework.org/schema/beans"
            xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
            xmlns:sec="http://www.springframework.org/schema/security"
            xmlns="http://www.springframework.org/schema/security"
            xsi:schemaLocation="http://www.springframework.org/schema/beans
            http://www.springframework.org/schema/beans/spring-beans.xsd
            http://www.springframework.org/schema/security
            http://www.springframework.org/schema/security/spring-security.xsd">

    <sec:http use-expressions="true">
        <sec:intercept-url pattern="/favicon.ico" access="permitAll"/>
        <sec:intercept-url pattern="/resources/**" access="permitAll"/>
        <sec:intercept-url pattern="/login" access="permitAll"/>
        <sec:form-login login-page="/login"
                        username-parameter="login"
                        password-parameter="password"
                        authentication-failure-url="/login?error"
                        authentication-success-handler-ref="successHandler"/>
        <sec:logout logout-url="/logout" logout-success-url="/login?logout"/>
        <sec:access-denied-handler error-page="/WEB-INF/views/error/403.jsp"/>
    </sec:http>

    <sec:authentication-manager>
        <sec:authentication-provider ref="userAuthenticationProvider"/>
    </sec:authentication-manager>

    <sec:global-method-security pre-post-annotations="enabled" secured-annotations="enabled">
        <sec:expression-handler ref="expressionHandler"/>
    </sec:global-method-security>

    <bean:bean id="expressionHandler" class="org.springframework.security.access.expression.method.DefaultMethodSecurityExpressionHandler">
        <bean:property name="permissionEvaluator" ref="permissionEvaluator"/>
    </bean:bean>

    <bean:bean id="permissionEvaluator" class="de.mark.project.security.UserPermissionEvaluator">
        <bean:constructor-arg ref="userSecurityService"/>
    </bean:bean>

    <bean:bean id="successHandler" class="de.mark.project.security.UrlAuthenticationSuccessHandler"/>
    <bean:bean id="userSecurityService" class="de.mark.project.service.UserService"/>

    <bean:bean name="userAuthenticationProvider" class="de.mark.project.security.UserAuthenticationProvider">
        <bean:constructor-arg ref="userSecurityService"/>
    </bean:bean>

</bean:beans>

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这是我的自定义评估者:

public class UserPermissionEvaluator implements PermissionEvaluator { …

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java spring spring-security

use*_*337

2014 03-15

5
推荐指数

1
解决办法

4958
查看次数

'this'关键字如何运作？

我无法理解正在bob.setAge = setAge做什么.有人可以解释它是如何工作的吗？

var bob = {
    name: "Bob Smith",
    age: 15
};

var frank = {
    name: "Frank Wolf",
    age: 32
};

function setAge(newAge) {
    this.age = newAge;
}

bob.setAge = setAge;
bob.setAge(23);

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javascript

use*_*337

lucky-day

1
推荐指数

1
解决办法

183
查看次数