我是一个新的转换为gradle.大多数任务都很好.但是我看到战争任务总是被跳过.当我在调试模式下运行时,我看到以下日志 -
09:12:34.889 [LIFECYCLE] [class org.gradle.internal.buildevents.TaskExecutionLogger]:war 09:12:34.889 [DEBUG] [org.gradle.api.internal.tasks.execution.ExecuteAtMostOnceTaskExecuter]开始执行任务' :war '09:12:34.889 [INFO] [org.gradle.api.internal.tasks.execution.SkipOnlyIfTaskExecuter]跳过任务':war'作为任务onlyIf为false.09:12:34.889 [DEBUG] [org.gradle.api.internal.tasks.execution.ExecuteAtMostOnceTaskExecuter]完成执行任务':war'09:12:34.889 [LIFECYCLE] [class org.gradle.internal.buildevents.TaskExecutionLogger] :战争SKIPPED
我不确定为什么只有我是假的.我在互联网上搜索过.但我没有找到任何相关的东西.
这是我的gradle文件 -
buildscript {
ext {
springBootVersion = '2.0.0.M2'
}
repositories {
mavenCentral()
maven { url "https://repo.spring.io/snapshot" }
maven { url "https://repo.spring.io/milestone" }
}
dependencies {
classpath("org.springframework.boot:spring-boot-gradle-plugin:${springBootVersion}")
}
}
// Apply the java-library plugin to add support for Java Library
apply plugin: 'java-library'
apply plugin: 'eclipse'
apply plugin: 'org.springframework.boot'
apply plugin: 'io.spring.dependency-management'
apply plugin: 'war'
apply plugin: 'checkstyle'
apply …Run Code Online (Sandbox Code Playgroud) 我们正在为我们的一个项目评估反应式编程框架.我刚刚学习了vert.x教程.我检查了一下RxJava的介绍.RxJava似乎更接近CompletableFuture.但是,尽管存在底层模式,RxJava和Vert.x都可以访问非阻塞编程.我很困惑他们之间有什么区别.在这方面,我将不胜感激.
作为问题的后续行动 -
同样的文件在spring-ftp中一次又一次地被拾取,但名称不同
我的application.xml中有以下配置
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns:int="http://www.springframework.org/schema/integration"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:file="http://www.springframework.org/schema/integration/file"
xmlns:int-stream="http://www.springframework.org/schema/integration/stream"
xmlns:int-ftp="http://www.springframework.org/schema/integration/ftp"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/integration
http://www.springframework.org/schema/integration/spring-integration.xsd
http://www.springframework.org/schema/integration/file
http://www.springframework.org/schema/integration/file/spring-integration-file.xsd
http://www.springframework.org/schema/integration/stream
http://www.springframework.org/schema/integration/stream/spring-integration-stream.xsd
http://www.springframework.org/schema/integration/ftp
http://www.springframework.org/schema/integration/ftp/spring-integration-ftp.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd">
<int:poller id="poller" task-executor="synchTaskExecutor" default="true" fixed-delay="1000" />
<beans:bean id="ftpClientFactory"
class="com.everge.springframework.integration.ftp.session.EvergeFtpSessionFactory">
<beans:property name="host" value="111.93.128.170"/>
<beans:property name="port" value="21"/>
<beans:property name="username" value="singha"/>
<beans:property name="password" value="singha16"/>
<beans:property name="clientMode" value="2"></beans:property>
</beans:bean>
<beans:bean id="ftpOutClientFactory"
class="org.springframework.integration.ftp.session.DefaultFtpSessionFactory">
<beans:property name="host" value="111.93.128.170"/>
<beans:property name="port" value="21"/>
<beans:property name="username" value="singha"/>
<beans:property name="password" value="singha16"/>
<beans:property name="clientMode" value="2"></beans:property>
</beans:bean>
<beans:bean id="synchTaskExecutor" class="org.springframework.scheduling.concurrent.ThreadPoolTaskExecutor">
<beans:property name="corePoolSize" value="1"></beans:property>
<beans:property name="maxPoolSize" value="1"></beans:property>
<beans:property …Run Code Online (Sandbox Code Playgroud) spring spring-integration spring-batch spring-integration-sftp
我想看看fs节点模块的代码,以便我了解这个模块是如何同步实现这个文件读取功能的。我确实尝试在 node_modules 文件夹中搜索。但我没有得到任何参考。你能帮我解决这个问题吗?
我是Cassandra的新手,正在尝试了解它的工作原理。假设是否写入多个节点。我的理解是,根据键的哈希值,它决定哪个节点拥有数据,然后进行复制。在读取数据时,键的哈希值确定哪个节点拥有数据,然后它进行响应。现在我的问题是,如果读取和写入是从始终具有数据的同一节点集进行的,那么读取不一致将如何发生,而Cassandra会返回陈旧数据?
我有以下代码 -
package com.test.rxjava;
import org.reactivestreams.Subscriber;
import org.reactivestreams.Subscription;
import io.reactivex.Flowable;
public class App1 {
public static void main(String[] args) {
Subscriber<Integer> subscriber = new Subscriber<Integer>() {
@Override
public void onSubscribe(Subscription s) {
}
@Override
public void onNext(Integer t) {
System.out.printf("Entry %d\n", t);
}
@Override
public void onError(Throwable t) {
System.err.printf("Failed to process: %s\n", t);
}
@Override
public void onComplete() {
System.out.println("Done");
}
};
Flowable.just(123).subscribe(subscriber);
}
}
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我期待在onNext方法中执行代码.但是没有任何反应.但是如果我用下面的代码替换最后一行,我确实得到了输出.
Flowable.just(123).subscribe((t) -> System.out.println(t));
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我不确定这里缺少什么.但绝对是肯定的.我是Rx世界的新手,可以帮助找出问题所在.提前致谢!
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