小编use*_*334的帖子

格式'%d'需要类型为'int'的参数,但参数2的类型为'int*'

我正在使用Linux,当我尝试使用此代码显示时:

#include <stdio.h>
#include <math.h>

int main()
{
    int a,b,c;
    int result;

    printf( "How Many Times Would You Like to Add: ");
    scanf( "%d", &a );
    //getchar();

    printf( "What Number Would You Like to Add: ");
    scanf( "%d", &b );
    //getchar();

    printf( "What Number Would You Like to Add to It?: ");
    scanf( "%d", &c );
    //getchar();

    for( int $i = 0; $i < a; $i++ )
    {
        result = b + c;
        printf( "%d", &result );
        printf( "\n" ); …
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c printf

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