我正在尝试为我的欢迎页面创建一个图像,并希望将字符串动态居中,否则使用不同的用户名(例如 John 和 Alexandra)就太糟糕了。
header("Content-type: image/png");
$string1 = "Hello!";
$string2 = "Welcome to our website!";
$srting3 = "$username";
$font1 = 5;
$font2 = 3;
$font3 = 3;
$img_w = 240;
$img_h = 64;
$image = imagecreatetruecolor ($img_w, $img_h);
$white = imagecolorallocate ($image, 255,255,255);
$black = imagecolorallocate ($image, 0, 0, 0);
imagefill($image, 0, 0, $white);
imagestring ($image, $font1, 110, 0, $string1, $black);
imagestring ($image, $font2, 60, 20, $string2, $black);
imagestring ($image, $font3, 105, 40, $string3, $black);
imagepng ($image);
imagedestroy($image);
Run Code Online (Sandbox Code Playgroud) 我有一个选择,我可以得到一些像数组一样的值 ["1","2","3"]
在每次更改时,我运行以下代码以获得连接到这些值的数组的结果
$('#event-courses-type').on('change',function(){
type = $('#event-courses-type').val();
console.log(type);
var var1 = ["4689 Leadership Award", "UKCC Level 1", "UKCC Level 2", "UKCC Level 3", "UKCC Level 4", "Old WHU Award", "None at present"];
var var2 = ["4689 Leadership Award", "GB-wide Level 1", "Old Level 1 (Pre January 2012)", "Level 2", "Level 3", "EHF", "FIH", "None at present"];
var var5 = ["D32/33", "A1 Assessor", "CTS", "IAPS", "PTLLS", "AVRA", "Umpire Educator Training", "Umpire Assessor Training"];
var var6 = ["D32/33", "A1 Assessor", "CTS", "IAPS", …Run Code Online (Sandbox Code Playgroud) 我有两个被调用的表conversations,users它们与conversation_user包含a user_id和conversation_id列的数据透视表绑定.
| conversation_id | user_id |
|-----------------|---------|
| 1 | 1 |
| 1 | 2 |
| 2 | 1 |
| 2 | 2 |
| 2 | 3 |
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我想向数据库发送一些用户ID并检索它们在一起的对话.
例如:
当我把1和2我必须接受conversation_id 1,当我发送1,2和3我必须接受conversation_id 2.
我怎么写这样的查询?
100,000
then paused
until renewal
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Algolia定价页面包含一个像这样的单元格的免费计划.
这是否意味着在100.000操作之后客户应该切换到付费计划,或者它是否像其他计划一样重置?
我在javascript中向对象添加方法时遇到问题.以下代码应返回一个数字,而是返回NaN.希望你能帮忙
function people(name, age){
this.name = name;
this.age = age;
this.numYearsLeft = pension();
}
function pension(){
numYears = 65 - this.age;
return numYears;
}
var andrews = new people("Andrews Green", 28);
console.log(andrews.numYearsLeft);
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