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是否可以在不扩展它的类方法中引用抽象类方法?

我正在学习构建简单行为Ai的教程.它的"大脑"类是抽象的,包含"跑步","成功","失败"等状态.现在在我的ai单元 - 机器人类我有一个方法来启动机器人的大脑.

    public void update(){

        if(Routine.getState()==null){
            Routine.start();
        }
        Routine.act(this, board);

    }
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现在这在java中是不可能的,因为它是对非静态方法的静态引用.我试图在这里引用的例程抽象类是这样的:

public abstract class Routine {

    public enum RoutineState{
        Success,
        Failure,
        Running
    }

    protected RoutineState state;

    protected Routine() { }

    public void start(){
        this.state = RoutineState.Running;
    }

    public abstract void reset();

    public abstract void act(droid droid, board board);

    public void succed(){
        this.state = RoutineState.Success;
    }

    public void Fail(){
        this.state = RoutineState.Failure;
    }

    public boolean isSuccess(){
        return state.equals(RoutineState.Success);
    }

    public boolean isFailure(){
        return state.equals(RoutineState.Failure);
    }

    public boolean isRunning(){
        return …
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java methods static abstract-class

5
推荐指数
1
解决办法
972
查看次数

我如何访问随机string.xml

一个简单的Quote生成器是有问题的,我已经构思了代码,并假设如果我将我的字符串保存在xml中它将起作用

<resources>
    <string name="app_name">"Lift Quote"</string>
    <string name="action_settings">Settings</string>
    <!-- put buttons in here -->
    <!-- here are the quotes -->
    <!-- inspiring -->
    <string name="s1">"He who has a why to live can bear almost any how." -Nietzche</string>
    <string name="s2">"Life is about making an impact, not making an income." –Kevin Kruse</string>
    <string name="s3">You miss 100% of the shots you don’t take. –Wayne Gretzky</string>
    <!-- deep -->
    <string name="s4">" A man's character is his fate. " -Heraclitus</string>
    <string name="s5">"Why do you stay in …
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java xml string android findviewbyid

1
推荐指数
1
解决办法
435
查看次数

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java ×2

abstract-class ×1

android ×1

findviewbyid ×1

methods ×1

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