小编MrA*_*me8的帖子

如何用Joda-Time计算两年中两个日期之间的差异......等等

import java.text.SimpleDateFormat;
import java.util.Date;
import org.joda.time.*;

public class Test {

  public static void main(String[] args) {

String dateStart = "01/01/2000 05:30";
String dateStop = "02/2/2001 06:31";

SimpleDateFormat format = new SimpleDateFormat("MM/dd/yyyy HH:mm");

Date d1 = null;
Date d2 = null;

try {
    d1 = format.parse(dateStart);
    d2 = format.parse(dateStop);

    DateTime dt1 = new DateTime(d1);
    DateTime dt2 = new DateTime(d2);

    System.out.print(Years.yearsBetween(dt1, dt2).getYears() + " years, ");
    System.out.print(Months.monthsBetween(dt1, dt2).getMonths() % 52 + " months, ");
    System.out.print(Weeks.weeksBetween(dt1, dt2).getWeeks() % 4 + " weeks, "); …
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java time date jodatime

19
推荐指数
1
解决办法
3万
查看次数

多个开关用于相同的情况

我有这个代码:

switch(month){
    case 1:
        System.out.print("January");
            break;
case 2:
    System.out.print("February");
        break;
case 3:
    System.out.print("March");
        break;
case 4:
    System.out.print("April");
        break;
case 5:
    System.out.print("May");
        break;
case 6:
    System.out.print("June");
        break;
case 7:
    System.out.print("July");
        break;
case 8:
    System.out.print("August");
        break;
case 9:
    System.out.print("September");
        break;
case 10:
    System.out.print("October");
        break;
case 11:
    System.out.print("November");
        break;
case 12:
    System.out.print("December");
        break;
}
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好的,所以这个代码100%完美地工作...对于int月.我有另一个int(avgMonth)只能保持相同的值(1-12),我想只有相同的输出(月份).如何在不必复制整个交换机和案例的情况下将avgMonth添加到此代码中?我尝试使用逗号(月,avgMonth)和&&(月&& avgMonth)以及+'s(月+ avgMonth),但无济于事.

java case switch-statement

1
推荐指数
1
解决办法
114
查看次数

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