小编Gal*_*ois的帖子

WindowsError:[错误5]尝试终止子进程(python)时拒绝访问

所以我有一个运行循环的python脚本,它通过subprocess.Popen调用程序A等待输出,然后保存输出,然后再次调用,依此类推.(这种情况一直发生在我设置为输入的一些运行中)

问题是我有一个计时器,这样每当程序A花费超过特定的threshold_time时,脚本就会用process.kill()杀死进程并继续进行下一次迭代.

问题是,即使300次运行似乎一切正常,但有时我会收到此错误:

    File "C:\Python27\lib\subprocess.py", line 1002, in terminate
    _subprocess.TerminateProcess(self._handle, 1)
    WindowsError: [Error 5] Access is denied
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然后脚本死了.

引用的脚本部分:

timeout = TIME_CONST
for run in runs:
    killed = False
    start = time.clock()
    p = subprocess.Popen("SOME.CMD", cwd=r"some_dir") 
    # Monitor process. If it hits threshold, kill it and go to the next run
    while p.poll() is None:
        time.sleep(20) 
        secs_passed = time.clock() - start

        ### the following was my initial buggy line ###
        #if secs_passed >= timeout: 

        ### corrected line after jedislight's answer …
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python subprocess popen

10
推荐指数
1
解决办法
8250
查看次数

如何反转它重复值的字典

所以,我有一个包含近100,000个(键,值)对的字典,而且大多数键映射到相同的值.例如,想象一下这样的事情:

mydict =  {'a': 1, 'c': 2, 'b': 1, 'e': 2, 'd': 3, 'h': 1, 'j': 3}
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我想要做的是反转字典,以便mydict中的每个值都将成为reverse_dict的一个键,并将映射到mydict上用于映射到该值的所有mydict.keys的列表.所以基于上面的例子,我会得到:

reversed_dict = {1: ['a', 'b', 'h'], 2:['e', 'c'] , 3:['d', 'j']} 
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我想出了一个非常昂贵的解决方案,我真的希望听到任何比我更有效的想法.

我昂贵的解决方案

reversed_dict = {}
for value in mydict.values():
    reversed_dict[value] = []
    for key in mydict.keys():
        if mydict[key] == value:
            if key not in reversed_dict[value]: reversed_dict[value].append(key)

Output >> reversed_dict = {1: ['a', 'b', 'h'], 2: ['c', 'e'], 3: ['d', 'j']}
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我真的很感激听到任何想法比我的更好更有效.谢谢!

python reverse dictionary

8
推荐指数
2
解决办法
3218
查看次数

Django: Difference between User.objects.profile.all() and User.objects.get_profile()?

I have a UserProfile model with related_name='profile' for the User FK.

Let's say I have a User obj, user1. If I want to get the UserProfile object from the user1, what is the difference between using user1.profile.all() and user1.get_profile() in terms of db hits and efficiency?

django django-models

0
推荐指数
1
解决办法
515
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python ×2

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