小编jam*_*ood的帖子

我试图更好地理解C#中的任务和异步操作,我已经运行了这个示例程序,但我对输出感到困惑.当我运行它时,程序有时不会在CallMethod中输出Console输出

int length = await task

有时确实如此,但当我取消注释时

Console.ReadLine()

它总是运行所有的CallMethod.

using System;
using System.IO;
using System.Threading;
using System.Threading.Tasks;

namespace Tasks1
{
    class Program
    { 
        static void Main(string[] args)
        {
            Task task = new Task(CallMethod);
            task.Start();
            task.Wait();
            //Console.ReadLine();
        }

    static async void CallMethod()
    {
        string filePath = "/Users/testname/Projects/Tasks1/Tasks1/Sample.txt";
        Task<int> task = ReadFile(filePath);

        Console.WriteLine("Other Work 1");
        Console.WriteLine("Other Work 2");
        Console.WriteLine("Other Work 3");

        int length = await task;
        Console.WriteLine(" Total Length: " + length);

        Console.WriteLine("After work 1");
        Console.WriteLine("After work 2");

    }

    static async Task<int> …