我在这个PHP else if语句中有一个错误(它是if语句的一部分):
Parse error: syntax error, unexpected '}' in /home1/tony1964/public_html/2v2tournaments/action.php
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意外'}'位于下面代码末尾的位置.我无法弄清楚为什么这不起作用.在此先感谢您的帮助.
else if (isset($_GET['do']) && $_GET['do'] === "reg_type_2") {
include('php-riot-api.php');
$summoner_name_input = $_POST['summonername'];
$summoner_name = str_replace(' ', '_', $summoner_name_input);
$summoner_region = $_POST['summonerregion'];
$verify_code_input = $_POST['verify_code'];
$verify_code = str_replace(' ', '_', $verify_code_input);
$instance = new riotapi($summoner_region);
$grab_data = $instance->getSummonerByName($summoner_name);
$decode_data = json_decode($grab_data);
$grab_id = $decode_data->{'id'};
var_dump($grab_id);
$grab_runes = $instance->getSummoner($grab_id,'runes');
$decode_runes = json_decode($grab_runes);
$rune_check = $decode_runes->{'name'};
if ($rune_check = $verify_code) {
$logged_user = $_SESSION['logged_user'];
if (!($stmt = $con->prepare("INSERT INTO `verified_summoners` (`Username`,`SummonerName`,`SummonerRegion`) …Run Code Online (Sandbox Code Playgroud) php ×1