小编Vik*_*han的帖子

我的代码是这样的

var data = [
    {id: 1, taskName: "Pete Hunt", standarDescription: "This is one comment", emplComment: "meaaow I am meeawo", empRating : "1"},
    {id: 2, taskName: "Pete Hunt", standarDescription: "This is one comment", emplComment: "meaaow I am meeawo", empRating : "1"},
    {id: 3, taskName: "Pete Hunt", standarDescription: "This is one comment", emplComment: "meaaow I am meeawo", empRating : "1"},
    {id: 4, taskName: "Pete Hunt", standarDescription: "This is one comment", emplComment: "meaaow I am meeawo", empRating : "1"},
    {id: 5, taskName: …

我收到上述错误

我的gradle看起来像这样

apply plugin: 'com.android.application'
apply plugin: 'kotlin-android'
apply plugin: 'kotlin-android-extensions'

android {
    compileSdkVersion 29
    buildToolsVersion "29.0.3"

    defaultConfig {
        applicationId "com.example.hypersignwalletcorekotlin"
        minSdkVersion 23
        targetSdkVersion 29
        versionCode 1
        versionName "1.0"

        testInstrumentationRunner "androidx.test.runner.AndroidJUnitRunner"
    }

    buildTypes {
        release {
            minifyEnabled false
            proguardFiles getDefaultProguardFile('proguard-android-optimize.txt'), 'proguard-rules.pro'
        }
    }

}
project.ext {
    walletcore_version = "2.0.5"
}
dependencies {
    implementation fileTree(dir: 'libs', include: ['*.jar'])
    implementation "org.jetbrains.kotlin:kotlin-stdlib-jdk7:$kotlin_version"
    implementation 'androidx.appcompat:appcompat:1.1.0'
    implementation 'androidx.core:core-ktx:1.2.0'
    implementation 'androidx.constraintlayout:constraintlayout:1.1.3'
    implementation "com.trustwallet:wallet-core:$walletcore_version"
    testImplementation 'junit:junit:4.12'
    androidTestImplementation 'androidx.test.ext:junit:1.1.1'
    androidTestImplementation 'androidx.test.espresso:espresso-core:3.2.0'
}

无法理解为什么会发生这种情况。

谢谢

我的验证类看起来像这样

<?php

namespace App\Http\Requests;

use App\Http\Requests\Request;

class PaymentRequest extends Request
{
    /**
     * Determine if the user is authorized to make this request.
     *
     * @return bool
     */
    public function authorize()
    {
        return true;
    }

    /**
     * Get the validation rules that apply to the request.
     *
     * @return array
     */
    public function rules()
    {
        $rules = array(

                       'invoiceid'=>'required',
                       'recieved_amount'=>'required',
                       'ref_no'=>'required',
                       'date'=>'required',
                       'comment'=>'required'
                       );


    }
}

我想验证recieved_amount为Money字段如果输入除money以外的任何其他内容,则应进行验证

任何人都可以帮助我

在这个JavaScript代码中,如果变量data没有那个字符.那么什么会分裂返回？

x = data.split('.');

它会是原始字符串的数组吗？

我试图用Laravel5中的json数组响应json

namespace App\Http\Controllers;
use Illuminate\Routing\ResponseFactory;
use Illuminate\Http\Request;
use Illuminate\Http\Response;
use App\Http\Requests;
use App\Http\Controllers\Controller;
use App\Event;

class EventsapiController extends Controller
{
    /**
     * Display a listing of the resource.
     *
     * @return \Illuminate\Http\Response
     */
    public function index()
    {
        //
        $events =  Event::All();

        return Response::json([

                'data'=>$events

        ],200);

    }
}

它给了我这个错误

Call to undefined method Illuminate\Http\Response::json() in Laravel5

那么我们如何在Laravel 5中传递json？,我已经知道laravel自动返回json数组,但我不想这样做

谢谢

我知道这是关于堆栈溢出的非常常见的问题我尝试了很少但它在我的场景中不起作用.

我的CollectionController看起来像这样.

<?php

namespace App\Http\Controllers;

use Illuminate\Http\Request;
use Illuminate\Support\Facades\Auth;
use App\Http\Requests;
use App\Http\Controllers\Controller;
use App\Http\Middleware\Role;
use Illuminate\Support\Facades\Input;
use App\User;
use App\Invoice;
use Session;
use Validator;


    class CollectionController extends Controller
    {
        /**
         * Display a listing of the resource.
         *
         * @return Response
         */

      public function __construct(){

        $this->middleware('role:collector'); // replace 'collector' with whatever role you need.
    }


      public function getHome(){

          $empid= Auth::user()->empid;
          $invoice = Invoice::where('Status','=',1)->orderBy('Id', 'desc')->get();


        return View('collectionmodule/home')->with(array('invoices'=>$invoice));

     }

       public function getPayment(){

    dd('sssss');
             $id =$invoiceid;
             $invoice = Invoice::where('Id','=',$id)->payments()->comments()->get();

             return View('collectionmodule/payment')->with(array('invoice'=>$id));

     } …

我的Ajax方法看起来像这样

$.post(url,{
            ajax_call:"putDonation",
            addresse:addresse,
            phone:phone,
            email:email,
            name:name,
            amount:amount,
            amountinwords:amountinwords
           }).done(function(data){

            console.log(data);

            var arr = [];

            try {
                  var str = "";
                  //convert to json string
                      arr = $.parseJSON(data); //convert to javascript array
                      $.each(arr,function(key,value){
                        str +="<li>"+value+"</li>";
                    });
                       alert(str);
                       $(".alert-danger").show();
                       $("#error").html(str);

              } catch (e) {
                  swal("Jay Gayatri !", 'Donation Sucessful', "success")
                  $("#donation")[0].reset();
              }


           })

我想展示一个像这样的甜蜜警报警告弹出窗口

   swal({   
                title: "Are you sure ?",   
                text: "You will not be able to recover this imaginary file!",   
                type: "warning",   
                showCancelButton: true,   
                confirmButtonColor: "#DD6B55",   
                confirmButtonText: "Yes, delete it!", …

我正在检查用户是否登录或不是这样

Class LoginController extends BaseController {

    public function getIndex(){
        return View::make('login',array('eventname' => Request::segment(1)));
    }

    public function postIndex(){

        $xx = User::where('email','=',Input::get('email'))->where('event','=',$requestedevent)->first();
        $eventattempt = Input::get('event');

        if ($xx){

                if(Auth::attempt($userDetails)){
                    if(Auth::check()){
                        // return var_dump($xx->id);
                        Session::put('username',Auth::user()->name);
                        Session::put('userid',Auth::user()->id);
                        Session::put('event',Auth::user()->event);
                        return Redirect::to($eventattempt.'/form/page1');
                    }
                } else {
                    return Redirect::to($eventattempt.'/login')->with('login_errors',true);
                }

        } else {
            return Redirect::to($eventattempt.'/login')->with('login_errors',true);
        }


    }

}

然后我在这样的Form控制器中做一个过滤器

<?php



Class FormController extends BaseController{



    public function __construct(){
        $this->beforeFilter('auth');
        $this->beforeFilter('eventcheck');


    }

  }

而我的filters.php看起来像这样

/*
|--------------------------------------------------------------------------
| Application & Route Filters
|--------------------------------------------------------------------------
|
| Below you will find the "before" …

我有一个NGINX服务器,我试图使用Let的加密添加SSL.

我的开发设置如下:

url : dev.domain.in
root: /var/www/dev/html

制作如下:

url : domain.in
root: /var/www/production/html

所以在我的nginx默认页面中,我有两个服务器块,一个用于开发,另一个用于生产

我想为两台服务器提供一个证书.

我知道根据Let's Encrypt网站的命令如下

cd/opt/letsencrypt ./letsencrypt-auto certonly -a webroot --webroot-path =/usr/share/nginx/html -d example.com -d www.example.com

但是,只有当SUBDOMAIN具有相同的webroot且在我的情况下不是真的时才能这样做.

那么我如何在这里添加CERT

请帮帮我

我编写了一个 MySql 查询来获取与最小 id 相关的列。看起来像这样

SELECT min(id) as ID,feed , idpropiedad FROM `registrofeed` WHERE feed=21

该表有 4 行，如下所示

所以根据我写的函数

function setLC()
 {
    
     $sql = "
SELECT min(id) as ID
  , feed 
  , idpropiedad 
  FROM `registrofeed` 
 WHERE feed=21
";
     $result = $this->localDb->execute($sql);
     $row=mysql_fetch_array($result);
     echo $sql;
     echo $row['idpropiedad'];
     $this->lastCode = $row['idpropiedad'];
 }

它为 idpropiedad 返回空字符串

任何人都可以帮我解决我哪里出错了

提前致谢