小编rea*_*dow的帖子

在AJAX请求之后,我正在努力解决问题.我正在从数据库中请求数据.这本身很有效,我处理数据并将其添加到PHP文件中的表中.该表包含一个标题,后跟数据.然后将该表传送到显示它的主页面.我的问题是我正在尝试格式化我在PHP中创建的按钮以进行格式化.这是带有数据请求的PHP

    if (mysqli_connect_errno()) {
        echo "Failed to connect to MySQL: " . mysqli_connect_error();
    }

    $sql = "SELECT LoginName FROM table";

    $res = mysqli_query($conn, $sql);

    if (mysqli_num_rows($res) > 0) {

        echo "<center>";
        echo "<table border='1'>";
        echo "<tr>";
        echo "<td>User</td>";
        echo "<td colspan=2 align=center>Available Functions</td>";
        echo "</tr>";

        while($row = mysqli_fetch_assoc($res)) {
            echo "<tr>";
            echo "<td>" . $row['User'] . "</td>";
            echo "<td><button type='button' class='smallbutton'>Delete User</button></td>";
            echo "<td><button type='button' class='smallbutton'>Change Password</button></td>";
            echo "</tr>";
        }
        echo "</table>";
        echo "</center>";
    } else {
        echo "";
    } …