示例JSON:
[{"steward":"EMPL-0102","description":"Elish Guage","emplyear":"2001","emplmonth":"Nov","empl":"HOME","perhour":"50"},
{"steward":"EMPL-9002","description":"Bush Harcourt","emplyear":"1990","emplmonth":"Nov","empl":"HOME","perhour":"50"},
{"steward":"EMPL-0102","description":"John Long","emplyear":"2001","emplmonth":"Nov","empl":"OFFICE","perhour":"50"},
{"steward":"EMPL-9002","description":"Wensel Gold","emplyear":"1990","emplmonth":"Nov","empl":"OFFICE","perhour":"50"}]
我需要一步一步的可行Delphi代码片段,将从PHP网站收到的JSON数据转换为本地数据库表.我曾尝试阅读一些文件,但无法理解我的要求的正确实施.
我从我的网站收到了JSON数据,并希望将这些数据解析到我的本地表中.
我希望评估JSON记录字段,例如表格格式(列和行).
我真的很喜欢它
FieldByName('field').AsString = JSONFieldByName('steward').AsString
然后到下一个JSON数组记录.