小编non*_*ame的帖子

template<class T>
class test
{
    public:
        test()
        {
        }

        test(T& e)
        {
        }

};

int main()
{

    test<double> d(4.3);

    return 0;
}

使用g ++ 4.4.1编译时出现以下错误:

g++ test.cpp -Wall -o test.exe
test.cpp: In function 'int main()':
test.cpp:18: error: no matching function for call to 'test<double>::test(double)
'
test.cpp:9: note: candidates are: test<T>::test(T&) [with T = double]
test.cpp:5: note:                 test<T>::test() [with T = double]
test.cpp:3: note:                 test<double>::test(const test<double>&)
make: *** [test.exe] Error 1

但是,这有效:

double a=1.1;
test<double> d(a);

为什么会这么讨厌？是否有可能g ++无法将文字表达式1.1隐式转换为double？谢谢.