小编Rya*_*tle的帖子

所以,我的CSS在3秒后将div移动到-40px.执行此操作后,div将移回其原始位置.这是代码:

#jsAlert {
    width: 100%;
    height: 40px;
    position: absolute;
    left: 0px;
    top: 0px;
    background-color: rgba(0, 0, 0, 0.6);
    animation:mymove 3s;
    animation-delay: 3s;

    /*Safari and Chrome*/
    -webkit-animation: mymove 2s;
    -webkit-animation-delay: 2s;
}

@keyframes mymove {
    from {top: 0px;}
    to {top: -40px;}
}

@-webkit-keyframes mymove /*Safari and Chrome*/
{
    from {top: 0px;}
    to {top: -40px;}
}

如何防止div返回其原始位置？

所以,我有一个工作的jquery脚本,当单击一个按钮时,页面会滚动到底部.我的目标是再次执行此操作,但我希望它滚动到页面顶部而不是滚动到底部.这是我的代码;

function scrolldown() { //Scroll to bottom
$("html, body").animate({ scrollTop: $(document).height() }, 1250);
};

function scrollup(){ //Scroll to top
$("html, body").animate({ scrollTop: $(document).top() }, 1250);
};

请帮我弄清楚我需要做什么,以便我的脚本按照我的意愿行事.谢谢!

所以,我正在尝试在我的服务器上创建一个PHP表,但即使它正确地连接到我的服务器也没有这样做.这是我的代码:

// alphacrmTableCreate.php | Ryan Castle | 09/04/2014 - This script CREATEs sables     tCompany and tPerson in the database 'alphacrm'

{ // Connect and test mySQL and specific DB

$hostname = "localhost";
$username = "root";
$password = "";

$databaseName = "alphacrm";

$dbConnected = @mysql_connect($hostname, $username, $password);
$dbSelected = @mysql_select_db($databaseName, $dbConnected);

$dbSuccess = true;
if ($dbConnected) {
    if (!$dbSelected) {
        echo "DB connection FAILED<br><br>";
        $dbSuccess = false;
    } else {
        echo "DB connection SUCCESSFUL<br><br>";
        $dbSuccess = true;
    }
} else
    echo …