小编DWa*_*e64的帖子

我在教自己C++,我对指针有点困惑(特别是在下面的源代码中).但首先,我继续向你展示我所知道的内容(然后将代码与此对比,因为我觉得好像存在一些矛盾).

我知道的:

int Age = 30;
int* pointer = &Age;

cout << "The location of variable Age is: " << pointer << endl;
cout << "The value stored in this location is: " << *pointer << endl;

指针保存内存地址.使用间接(取消引用)运算符(*),可以访问存储在指针的内存位置的内容.在本书的代码中,我无法理解......

cout << "Enter your name: ";
string name;
getline(cin, name); //gets full line up to NULL terminating character

int CharsToAllocate = name.length() + 1; //calculates length of string input
                          //adds one onto it to adjust for NULL character
char* CopyOfName = new …

我无法理解C风格的字符串是什么.新年快乐

我所知道的:指针包含一个内存地址.取消引用指针将为您提供该内存位置的数据.

int x = 50;
int* ptr = &x;    //pointer to an integer, holds memory address of x

cout << "&x: " << &x << endl;  //these two lines give the same output as expected
cout << "ptr: " << ptr << endl;

cout << "*ptr: " << dec << (*ptr) << endl;  //prints out decimal number 50
                                           //added dec, so the program doesnt 
                //continue to printout hexidecimal numbers like it did for the 
                 //the memory addresses above
cout …