我遇到了很大的麻烦,因为我需要通过设计一些输入类型来解决问题.我有类似的东西:
.registration_form_right input:not([type="radio")
{
//Nah.
}
Run Code Online (Sandbox Code Playgroud)
但我也不想设置复选框样式.
我试过了:
.registration_form_right input:not([type="radio" && type="checkbox"])
.registration_form_right input:not([type="radio" && "checkbox"])
.registration_form_right input:not([type="radio") && .registration_form_right input:not(type="checkbox"])
Run Code Online (Sandbox Code Playgroud)
怎么用&&?我需要尽快使用||,我认为使用方法是一样的.
更新:
我仍然不知道如何使用||和&&正确.我在W3文档中找不到任何内容.
我想这样做:
$this->get('translator')->trans('notice.unregistered', array(), 'index');
Run Code Online (Sandbox Code Playgroud)
在Twig模板内部,所以我不必将其作为参数传递.怎么样?
我无法在我的 docker 容器中运行任何二进制文件。
Dockerfile:
FROM ubuntu:eoan AS compiler-build
RUN apt-get update && \
dpkg --add-architecture i386 && \
apt-get install -y gcc \
gcc-multilib \
make \
cmake \
git \
python3.8 \
bash
WORKDIR /home
ADD . /home/pawn
RUN mkdir build
WORKDIR /home/build
ENTRYPOINT ["/bin/bash"]
CMD ["/bin/bash"]
Run Code Online (Sandbox Code Playgroud)
我什至不能使用file内置:
[root@LAPTOP-EJ5BH6DJ compiler]:~/dev/private/SAMP/compiler (v13.11.0) (master) dc run compiler file bash
/usr/bin/file: /usr/bin/file: cannot execute binary file
Run Code Online (Sandbox Code Playgroud) 这是PHP的最后一次尝试,如果失败了,我会尝试使用JS.所以我的目标是通过PHP在FB页面上发布"页面名称":这就是我想要的

但我得到的只是如下图所示.此外,它仅对此配置文件可见(不是对喜欢/ etc的朋友/ ppl).

这是我目前的代码
function post_facebook($data=null, $redir = null){
$result = "";
require_once (ROOT. "/apps/configuration/models/ConfigurationItem.php");
require_once (ROOT . "/components/facebook/facebook.php");
$this->ConfigurationItem = new ConfigurationItem($this->getContext());
$row=$this->ConfigurationItem->findByCatKeyItemKey('system','facebook_login');
$apiid=$row['value']; <= Correct apiid
$row=$this->ConfigurationItem->findByCatKeyItemKey('system','facebook_pass');
$secret=$row['value']; <= Correct secret key
$facebook = new Facebook(array(
'appId' => $apiid,
'secret' => $secret,
'cookie' => true,
));
$session = $facebook->getSession();
$me = null;
if ($session) {
try {
$uid = $facebook->getUser();
$me = $facebook->api('/me');
} catch (FacebookApiException $e) {
error_log($e);
}
$message=$data['facebook_text'];
$attachment = array(
'message' => $data['facebook_text'], …Run Code Online (Sandbox Code Playgroud) 我想在Bundle/Resources/config中添加一个新的配置文件.我已经尝试过http://symfony.com/doc/current/cookbook/bundles/extension.html,但它不能正常工作我得到了
没有扩展程序可以加载"mailbroker_mail_details"的配置
我的文件:
MailbrokerMailDetailsExtension.php
<?php
namespace Mailbroker\MailDetailsBundle\DependencyInjection;
use Symfony\Component\DependencyInjection\ContainerBuilder;
use Symfony\Component\Config\FileLocator;
use Symfony\Component\HttpKernel\DependencyInjection\Extension;
use Symfony\Component\DependencyInjection\Loader;
class MailbrokerMailDetailsExtension extends Extension
{
/**
* {@inheritDoc}
*/
public function load(array $configs, ContainerBuilder $container)
{
$configuration = new Configuration();
$config = $this->processConfiguration($configuration, $configs);
$loader = new Loader\YamlFileLoader($container, new FileLocator(__DIR__.'/../Resources/config'));
$loader->load('services.yml');
$loader->load('canonisers.yml');
}
public function getAlias()
{
return 'mailbroker_mail_details';
}
}
Run Code Online (Sandbox Code Playgroud)
的configuration.php
<?php
namespace Mailbroker\MailDetailsBundle\DependencyInjection;
use Symfony\Component\Config\Definition\Builder\TreeBuilder;
use Symfony\Component\Config\Definition\ConfigurationInterface;
class Configuration implements ConfigurationInterface
{
/**
* {@inheritDoc}
*/
public function getConfigTreeBuilder()
{
$treeBuilder …Run Code Online (Sandbox Code Playgroud) 今天我试图包含返回对象的文件.我总是使用require_once,但是现在我注意到它的奇怪行为.
文件main.php
$lang = false;
$lang->name = "eng";
$lang->author = "Misiur";
$lang->text = "Text is test";
$lang->undefined = "Undefined";
return $lang;
Run Code Online (Sandbox Code Playgroud)
文件index.php
$lang = include('langs/eng/main.php');
var_dump($lang);
echo "<br />";
$lang = require('langs/eng/main.php');
var_dump($lang);
echo "<br />";
$lang = require_once('langs/eng/main.php');
var_dump($lang);
Run Code Online (Sandbox Code Playgroud)
结果
object(stdClass)#9 (4) { ["name"]=> string(3) "eng" ["author"]=> string(6) "Misiur" ["text"]=> string(12) "Text is test" ["undefined"]=> string(9) "Undefined" }
object(stdClass)#10 (4) { ["name"]=> string(3) "eng" ["author"]=> string(6) "Misiur" ["text"]=> string(12) "Text is test" ["undefined"]=> string(9) "Undefined" }
bool(true)
Run Code Online (Sandbox Code Playgroud)
为什么会那样?我认为require和require_once是一回事,只有require_once更安全,因为它不会重复包含.
谢谢. …
将函数绑定到同一上下文时,结果引用每次都不同.
function foobar() {
return 1;
}
var foo = foobar.bind(this);
var bar = foobar.bind(this);
console.log(foo === bar); // NopeRun Code Online (Sandbox Code Playgroud)
我想在页面上发帖 - 通过我的网站..我没有找到任何可以帮助我的文档.谷歌的结果也没有给出答案.
function post_facebook($data=null){
$result = "";
require_once (ROOT. "/apps/configuration/models/ConfigurationItem.php");
require_once (ROOT . "/components/facebook/facebook.php");
$this->ConfigurationItem = new ConfigurationItem($this->getContext());
$row=$this->ConfigurationItem->findByCatKeyItemKey('system','facebook_login');
$apiid=$row['value'];
$row=$this->ConfigurationItem->findByCatKeyItemKey('system','facebook_pass');
$secret=$row['value'];
$facebook = new Facebook(array(
'appId' => $apiid,
'secret' => $secret,
'cookie' => true,
));
$session = $facebook->getSession();
print_r($session);
$me = null;
if ($session) {
try {
$uid = $facebook->getUser();
$me = $facebook->api('/me');
} catch (FacebookApiException $e) {
error_log($e);
}
$message=$data['facebook_text'];
$attachment = array(
'message' => $data['facebook_text'],
'name' => $data['name'],
'link' => $this->getLinkToLatestNews(),
'description' => '',
);
if($data['thumb_file_tree_id'] …Run Code Online (Sandbox Code Playgroud) 我必须使用基于回调的API,但我想保留我的异步函数.这就是为什么我要写一个depromisify函数:
const depromisify = fn => {
if (!(fn[Symbol.toStringTag] === 'AsyncFunction')) {
return fn;
}
// Can be `async` as the caller won't use assignment to get the result - it's all bound to the `cb`
return async function () {
const args = [...arguments];
const cb = args.pop();
try {
return cb(null, await fn.apply(this, args));
} catch (e) {
return cb(e);
}
};
};
const normal = function(cb) {
this.hello();
cb(null, true);
};
const promised = async function() { …Run Code Online (Sandbox Code Playgroud)