我正在尝试在 Spring Boot 项目启动后运行一些方法。@EventListener(ApplicationReadyEvent.class)
我在项目启动后想要运行的方法上方使用注释。但它一次只启动一种方法。我想同时启动多种方法。这是 的预期行为吗@EventListener(ApplicationReadyEvent.class)
?
查询一
select * from state where state_name = 'Florida';
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当我在管理员中运行上面的查询时,它需要从
0.032秒至0.058秒
解释分析
Seq Scan on state (cost=0.00..3981.50 rows=1 width=28) (actual time=1.787..15.047 rows=1 loops=1)
Filter: (state_name = 'Florida'::citext)
Rows Removed by Filter: 50
Planning Time: 0.486 ms
Execution Time: 15.779 ms
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查询二
select
property.id as property_id ,
full_address,
street_address,
street.street,
city.city as city,
state.state_code as state_code,
zipcode.zipcode as zipcode
from
property
inner join street on
street.id = property.street_id
inner join city on
city.id = property.city_id
inner …
Run Code Online (Sandbox Code Playgroud) 我有以下代码,它使用 firebase-admin 使用 Firebase 云消息传递发送消息
Message message = null;
message = Message.builder().putData("From", fromTel).putData("To", toTel).putData("Text", text)
.setToken(registrationToken).build();
String response = null;
try {
response = FirebaseMessaging.getInstance().sendAsync(message).get();
responseEntity = new ResponseEntity<String>(HttpStatus.ACCEPTED);
} catch (InterruptedException | ExecutionException e) {
e.printStackTrace();
}
System.out.println("Successfully sent message: " + response);
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上面的代码工作正常。但我需要发送“高优先级”消息,以便设备可以在打瞌睡模式下接收它们。
如何使消息成为“高优先级”?
我正在使用 Android 版 Appium
以下适用于单击元素
driver.findElement(By.xpath("//*[@resource-id='com.app.android:id/prelogin_signup']")).click();
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但我试图检查屏幕上是否有一个元素,并且我尝试了以下操作
if (driver.findElement(By.xpath("//*[@resource-id='com.app.android:id/prelogin_signup']")).isDisplayed()) {
System.out.println("FOUND");
} else {
System.out.println("NOT FOUND!");
}
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但它返回一个异常说
INFO: HTTP Status: '405' -> incorrect JSON status mapping for 'unknown error' (500 expected)
org.openqa.selenium.WebDriverException: Method is not implemented
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如何检查某个元素是否在屏幕上?