我是R的初学者,并没有找到解决以下问题的方法.任何帮助将非常感激!
我有一个data.frame,并希望用定义的其他值替换列的某些值.
data.frame
date<-c("19921231","19931231","19941231","19941231","19931231","19941231")
variable<-c("a","a","a","b","b","b")
value<-c(1:6)
dataframe <- data.frame(date,variable,value)
试图解决问题
yearend<-c("19921231","19931231","19941231")
year<-c("1992","1993","1994")
map = setNames(yearend,year)
dataframe[] = map[dataframe]
错误信息
Error in map[dataframe] : invalid subscript type 'list'
问题显然是,它不是一个矩阵.解决这个问题最有效的方法是什么？如果我想替换"真实"字符,例如"BGSFDS"和"BASF stock",它也应该有用.
我是R的初学者并且有问题.真的很感激任何帮助!当我在以下(简化)的情况下应用for循环时,我收到一条错误消息,说"替换有5行,数据有4"
Country <- c("Germany", "France", "Italy", "Spain")
Unemploy <- c(2, 3, 4, 10)
Growth <- c(2, 7, 6, 9)
data <- data.frame(Country, Unemploy, Growth)
for (i in data$Country) {
if (identical(data$Country[i], "France")) {
data$Growth[i] <- "5"
} else {
data$Growth[i] <- "2"
}
}
发出以下消息:
Error in `$<-.data.frame`(`*tmp*`, "Growth", value = c("2", "2", "2", :
replacement has 5 rows, data has 4