小编Nic*_*ick的帖子

AngularJS错误:TypeError:v2.login不是函数

我想在单击登录按钮时调用登录功能,但不断在标题中收到错误消息.有人可以在我的脚本中指出错误吗?

login.js代码如下:

/*global Firebase, angular, console*/

'use strict';
// Create a new app with the AngularFire module
var app = angular.module("runsheetApp");

app.controller("AuthCtrl", function ($scope, $firebaseAuth) {
    var ref = new Firebase("https://xxxxx.firebaseio.com");
    function login() {
        ref.authWithPassword({
            email    : "xxxxx",
            password : "xxxx"
        }, function (error, authData) {
            if (error) {
                console.log("Login Failed!", error);
            } else {
                console.log("Authenticated successfully with payload:", authData);
            }
        });
    }
});
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<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.21/angular.min.js"></script>
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login.html的代码如下:

<div class="container" style="max-width: 300px">
    <form class="form-signin">       
      <h2 class="form-signin-heading" style="text-align: center">Please Sign In</h2>
      <input …
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angularjs firebase angularjs-ng-click firebase-authentication

22
推荐指数
5
解决办法
4万
查看次数

从Pandas DataFrame返回单个单元格值

我想问一个问题是这个帖子的扩展:

根据pandas中列的值从DataFrame中选择行.

该线程的代码如下所示:

import pandas as pd
import numpy as np
df = pd.DataFrame({'A': 'foo bar foo bar foo bar foo foo'.split(),
               'B': 'one one two three two two one three'.split(),
               'C': np.arange(8), 'D': np.arange(8) * 2})
print(df)
#      A      B  C   D
# 0  foo    one  0   0
# 1  bar    one  1   2
# 2  foo    two  2   4
# 3  bar  three  3   6
# 4  foo    two  4   8
# 5  bar    two  5  10 …
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python pandas

6
推荐指数
1
解决办法
2万
查看次数

检测旋转完成后移动到新场景

当车轮停止旋转时,我正试图移动到另一个场景.我的代码如下所示.我无法弄清楚如何检测速度何时达到0.0?

import SpriteKit
import GameplayKit

class GameplayScene: SKScene {

    var player: Player?;

    override func didMove(to view: SKView) {
        player = self.childNode(withName: "spinner") as! Player?;
    }

    override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent?) {
        for touch in touches {
            let location = touch.location(in: self)
            if atPoint(location).name == "play_button" {
               spin()
            }
        }
    }

    func spin () {
        let random = GKRandomDistribution(lowestValue: 20, highestValue: 90)
        let r = random.nextInt()
        player?.physicsBody = SKPhysicsBody(circleOfRadius: CGFloat(self.frame.width))
        player?.physicsBody?.affectedByGravity = false
        player?.physicsBody?.isDynamic = true
        player?.physicsBody?.allowsRotation = …
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ios sprite-kit swift

5
推荐指数
1
解决办法
95
查看次数

Swift音频播放速度

我正在开发一款主要精灵是旋转轮的游戏.我想将音频与旋转车轮相关联,当车轮减速时,它会改变音高.当车轮停止旋转时,我希望声音效果停止.有人能指出我正确的方向吗?

在我的游戏场景中,我有以下代码:

override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent?) {

    for touch in touches {
        let location = touch.location(in: self)
        //Start spinning the wheel
        if atPoint(location).name == "play_button" {
            player?.physicsBody?.angularVelocity = 0
            player?.rotatePlayer()

            //Click back button
        } else if atPoint(location).name == "back_button" {
            let play_scene = CharacterSelectScene(fileNamed: "CharacterSelect")
            play_scene?.scaleMode = .aspectFill
            self.view?.presentScene(play_scene!, transition: SKTransition.doorsOpenVertical(withDuration: 1))
        } else if atPoint(location).name == "settings_button" {
            let play_scene = SettingsScene(fileNamed: "SettingsScene")
            play_scene?.scaleMode = .aspectFill
            self.view?.presentScene(play_scene!, transition: SKTransition.doorsOpenVertical(withDuration: 1))
        }
    }
}

override func …
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avaudioplayer sprite-kit skscene swift

5
推荐指数
1
解决办法
187
查看次数

为SKSprite Game创建一个登录页面

我正在使用许多SKScene和Sprite对象在xcode中创建游戏(Swift).我想创建一个场景(设置场景)来捕捉玩家的姓名,电子邮件,性别等.我该如何解决这个问题?如何捕获用户的输入.SKScenes不允许在UI中输入字段/值?

谢谢

sprite-kit skspritenode skscene swift

3
推荐指数
1
解决办法
358
查看次数