我有两个字符串
string1="abc def ghi"
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和
string2="def ghi abc"
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如何在不破坏单词的情况下获得这两个字符串相同?
我正在尝试导入形状。我遇到以下错误。我安装了较低版本的NumPy仍然问题没有解决。谢谢你!
import shap
ImportError Traceback (most recent call last)
/tmp/ipykernel_22681/948769371.py in <module>
----> 1 import shap
~/jupyter/environment/lib/python3.8/site-packages/shap/__init__.py in <module>
10 warnings.warn("As of version 0.29.0 shap only supports Python 3 (not 2)!")
11
---> 12 from ._explanation import Explanation, Cohorts
13
14 # explainers
~/jupyter/environment/lib/python3.8/site-packages/shap/_explanation.py in <module>
10 from slicer import Slicer, Alias, Obj
11 # from ._order import Order
---> 12 from .utils._general import OpChain
13
14 # slicer confuses pylint...
~/jupyter/environment/lib/python3.8/site-packages/shap/utils/__init__.py in <module>
----> 1 from ._clustering import hclust_ordering, …Run Code Online (Sandbox Code Playgroud) String tect = "A to B";
Pattern ptrn = Pattern.compile("\\b(A.*)\\b");
Matcher mtchr = ptrn.matcher(tr.text());
while(mtchr.find()) {
System.out.println( mtchr.group(1) );
}
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我正在获得输出,A to B但我想要to B.
请帮我.
我有一个清单L = [1,2,3].从列表和输出中获取2个元素的所有可能独特组合的最佳方法是以迭代的方式进行:
第1次迭代= 1次,第2次迭代= 1次,第3次迭数= 2次3次
谢谢