小编use*_*929的帖子

HIbernate映射异常:PropertyNotFoundException:找不到setter

我有两个POJO,STOCK和STOCK_DETAILS(一对多的关系).我还有一个接口IAUDITLOG(有两种方法).我需要用BOTH POJO实现这个接口,并希望在这些方法中编写一些实现.但是当我用子类"STOCKDETAILS"实现IAUDITLOG接口时,它会给出异常"你应该有setter属性"

股票类别:

@Entity
@Table(name = "stock")
public class Stock implements java.io.Serializable, IAuditLog
{   
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Basic(optional = false)
    @Column(name = "id")
    private Integer stockId;

    @Column(name = "STOCK_CODE")
    private String stockCode;

    @Column(name = "STOCK_NAME")
    private String stockName;

    @OneToMany( fetch = FetchType.LAZY, mappedBy = "stock")
    public Set<StockDetail> stockDetails = new HashSet<StockDetail>(0);


    public Set<StockDetail> getStockDetails() {
        return stockDetails;
    }

    public void setStockDetails(Set<StockDetail> stockDetails) {
        this.stockDetails = stockDetails;
    }

    public Integer getStockId() {
        return stockId;
    }

    public void setStockId(Integer stockId) { …
Run Code Online (Sandbox Code Playgroud)

java spring hibernate hibernate-mapping

9
推荐指数
2
解决办法
2万
查看次数

如何将@RequestParam绑定到spring MVC中的object?

我想通过AJAX发出POST请求,我还想将整个类对象绑定到请求,并且我希望通过@requestParam注释接收该请求.我知道它可以用@requestBody注释完成,但我很想知道:我们可以用@requestParam注释来做吗?

一个Ajax代码:

var restDTO{
    id: 3,
    name: "hello"
}

 $.ajax({
          url: url, 
          type: 'POST',
          dataType: 'json',
          contentType: 'application/json',
          mimeType: 'application/json',
          data: JSON.stringify({RestDTO : restDTO}),          
          success: function(data) 
    {
    }
Run Code Online (Sandbox Code Playgroud)

我有RestDTO

Class RestDTO 
{

    int id;
    String name;

    //getter and setter

}
Run Code Online (Sandbox Code Playgroud)

在控制器中

public String content(@RequestParam RestDTO restDTO){...}
Run Code Online (Sandbox Code Playgroud)

我应该怎么做才能运行此代码?

从ajax发送数据应该更改什么?

我是否需要在服务器上更改以接收带@requestParam注释的RestDto对象?

java ajax spring json spring-mvc

6
推荐指数
3
解决办法
4万
查看次数

如何在EntityListeners中注入EntityManager

我需要在EntityListener类中注入EntityManager,以便我可以对它执行CRUD操作.

POJO:

@Entity
@EntityListner(AuditLogging.class)
class User
{
      //Getter / setter of properties
}
Run Code Online (Sandbox Code Playgroud)

AuditLogging(Listner类)

public class AuditInterceptor
{

  @PersistenceContext
  EntityManager entityManager;

  public void setEntityManager(EntityManager entityManager)
  {
    this.entityManager = entityManager;
  }

  @PrePersist
  public void prePersist(Object obj)
  {
     // Here I want to use ENTITY manager object so that I can perform CRUD operation
     // with prePersist coming object.

      entityManager.unwrap(Session.class).save(obj);

     // But I am getting NULL POINTER EXCEPTION for entity manager object 
   }
Run Code Online (Sandbox Code Playgroud)

}

JDBC-config.xml中

<bean id="entityManagerFactory"
        class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
        <property name="dataSource" ref="dataSource" /> …
Run Code Online (Sandbox Code Playgroud)

java spring hibernate spring-mvc spring-data-jpa

4
推荐指数
2
解决办法
4711
查看次数