小编Sta*_*key的帖子

给定对特定目录角色的成员的查询，我想返回相应用户的列表。我所拥有的是这样的：

IDirectoryObjectCollectionWithReferencesRequest request = graphServiceClient.directoryRoles(roleId).members().buildRequest();
IDirectoryObjectCollectionWithReferencesPage page = request.select(USER_FIELDS_TO_RETURN).get();
List<DirectoryObject> objects = page.getCurrentPage();
IDirectoryObjectCollectionWithReferencesRequestBuilder builder = page.getNextPage();
while (builder != null) {
    request = builder.buildRequest();
    page = request.select(USER_FIELDS_TO_RETURN).get();
    objects.addAll(page.getCurrentPage());
    builder = page.getNextPage();
}
return objects.stream().filter(o -> o.oDataType.equals("#microsoft.graph.user")).map(o -> new User()).collect(Collectors.toList());

问题出在 return 语句上。仅过滤用户对象（找不到比比较 oDataType 更优雅的方法）并返回带有 o 内容的用户对象：

objects.stream().filter(o -> o.oDataType.equals("#microsoft.graph.user")).map(o -> {
        // the only thing that I could think of is to do some weird
        // serialization/deserialization logic here which is a bad solution
        // for anything other than …

这是我到目前为止所拥有的，但我似乎无法找到 .filter(s)，是否以其他方式完成？

        IGroupCollectionRequest request = graphServiceClient.groups().buildRequest();
        IGroupCollectionPage page = request.get();
        IGroupCollectionRequestBuilder builder = page.getNextPage();
        while (builder != null) {
            request = builder.buildRequest();
            page = request.get();
            builder = page.getNextPage();
        }