小编sle*_*731的帖子

在t_stamp列下的我的数据库中,我有日期例如

2013-11-26 01:24:34

从同一列我只想得到日期

2013-11-26

我怎样才能做到这一点？谢谢!

SELECT COUNT(*) FROM Table1 WHERE user = "carl" AND ans = "yes"

然后我想将此查询的输出除以另一个查询,例如输出为10.所以它将像:

10 / SELECT COUNT(*) From Table1 WHERE user = "carl"

如何正确的语法？

谢谢

我编辑了这个问题导致下面提到的答案,当使用while和begin时,它应该在一个存储过程中.

所以现在我在存储过程中运行它,但我仍然收到错误.

counter;
while counter < 2
begin
GOTO counter

SELECT var1 AS LOCATION,
  ROUND(sum(CASE WHEN t2.tagid = var2 THEN t2.floatvalue ELSE 0 END), 2) AS MR
  ROUND(sum(CASE WHEN t2.tagid = var3 THEN t2.floatvalue ELSE 0 END), 2) AS Flw,
  ROUND(sum(CASE WHEN t2.tagid = var4 THEN t2.floatvalue ELSE 0 END), 2) AS Prs,
  ROUND(sum(CASE WHEN t2.tagid = var5 THEN t2.floatvalue ELSE 0 END), 2) AS Lvl
FROM table2 t2

INNER JOIN table1  t1
  ON t1.id = t2.tagid

WHERE t2.t_stamp = …