小编Kri*_*hna的帖子

我需要获得员工姓名包含"kumar"且年龄大于26的员工数.我使用Java 8流来迭代收集,我能够找到具有上述条件的员工数.

但是,与此同时,我需要打印员工的详细信息.

这是我使用Java 8流的代码:

public static void main(String[] args) {

    List<Employee> empList = new ArrayList<>();

    empList.add(new Employee("john kumar", 25));
    empList.add(new Employee("raja", 28));
    empList.add(new Employee("hari kumar", 30));

    long count = empList.stream().filter(e -> e.getName().contains("kumar"))
                          .filter(e -> e.getAge() > 26).count();
    System.out.println(count);
}

传统方式:

public static void main(String[] args){
   List<Employee> empList = new ArrayList<>();

    empList.add(new Employee("john kumar", 25));
    empList.add(new Employee("raja", 28));
    empList.add(new Employee("hari kumar", 30));
    int count = 0;
    for (Employee employee : empList) {

        if(employee.getName().contains("kumar")){
            if(employee.getAge() > 26)
            {
                System.out.println("emp details :: …