我试图在PHP中$_COOKIE调用setcookie()函数后立即访问cookie的值(使用).当我这样做时,$_COOKIE['uname']没有设定.为什么?
但是,请注意,$_COOKIE['uname']在下次执行脚本时(例如在页面刷新之后)按预期设置.
setcookie('uname', $uname, time() + 60 * 30);
echo "Cookie value: " . $_COOKIE['uname'];
Run Code Online (Sandbox Code Playgroud) 我是一个Python人.学习C语言,我一直在尝试在C中实现二进制搜索树.我写下了代码,我已经尝试了几个小时但是,无法按预期获得输出.请帮忙!
请指正.
#include<stdlib.h>
#include<stdio.h>
typedef int ElementType;
typedef struct TreeNode {
ElementType element;
struct TreeNode *left, *right;
} TreeNode;
TreeNode *createTree(){
//Create the root of tree
TreeNode *tempNode;
tempNode = malloc(sizeof(TreeNode));
tempNode->element = 0;
tempNode->left = NULL;
tempNode->right = NULL;
return tempNode;
}
TreeNode *createNode(ElementType X){
//Create a new leaf node and return the pointer
TreeNode *tempNode;
tempNode = malloc(sizeof(TreeNode));
tempNode->element = X;
tempNode->left = NULL;
tempNode->right = NULL;
return tempNode;
}
TreeNode *insertElement(TreeNode *node, ElementType X){
//insert element to …Run Code Online (Sandbox Code Playgroud) 在我的localhost中打开PHP页面时显示PHP源代码.这看起来很奇怪.我在Mac OS X Snow Leopard上使用PHP 5.3.1.
$ php --version
PHP 5.3.1 (cli) (built: Feb 28 2010 15:02:51)
Copyright (c) 1997-2009 The PHP Group
Zend Engine v2.3.0, Copyright (c) 1998-2009 Zend Technologies
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我在我的机器上运行默认的httpd网络服务器./etc/apache2/httpd.conf文件有以下行来加载php模块:
LoadModule php5_module libexec/apache2/libphp5.so
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httpd.conf文件语法没问题.
$ httpd -t
Syntax OK
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我错过了什么吗?请指教!
谢谢!
我无法通过php连接到mysql.在PHP中[error] [client 127.0.0.1] PHP Warning: mysql_connect(): No such file or directory执行mysql_connect()函数时,它会在apache错误日志中生成错误消息.
运行php -m命令时请查看警告消息:
$ php -m | grep mysql
PHP Warning: PHP Startup: Unable to load dynamic library '/usr/lib/php/extensions/no-debug-non-zts-20090626/msql.so' - dlopen(/usr/lib/php/extensions/no-debug-non-zts-20090626/msql.so, 9): image not found in Unknown on line 0
PHP Warning: PHP Startup: Unable to load dynamic library '/usr/lib/php/extensions/no-debug-non-zts-20090626/php_mysql.dll' - dlopen(/usr/lib/php/extensions/no-debug-non-zts-20090626/php_mysql.dll, 9): image not found in Unknown on line 0
PHP Warning: PHP Startup: Unable to load dynamic library '/usr/lib/php/extensions/no-debug-non-zts-20090626/php_mysqli.dll' - dlopen(/usr/lib/php/extensions/no-debug-non-zts-20090626/php_mysqli.dll, 9): …Run Code Online (Sandbox Code Playgroud) 我一直在想为什么将python安装在名为Frameworks的目录中?(虽然不是Framework)
$ which python
/Library/Frameworks/Python.framework/Versions/2.7/bin/python
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有人请解释!谢谢!
鉴于两套
a = [5,3,4,1,2,6,7]
b = [1,2,4,9]
c = set(a) - set(b)
# c -> [5,3,6,7]
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是否可以计算从'a'中删除了多少项?
我正在尝试在Twitter REST API(JSON格式)上进行AJAX.我做了下面的事情,但是,没有任何反应.
没有从服务器(Twitter)得到任何响应.我错过了什么?
function getRecentTweet(){
twitterUsername = document.getElementById("twitterUsername").value;
if(window.XMLHttpRequest){
xhr = new XMLHttpRequest();
}
else{
xhr = new ActiveXObject("Microsoft.XMLHTTP");
}
xhr.open("GET", "http://api.twitter.com/1/statuses/user_timeline/" + twitterUsername + ".json", true);
xhr.send(null);
xhr.onreadystatechange = function(){
if (xhr.readyState == 4) {
if(xhr.status == 200) {
var jsonObj = eval(responseJSON);
document.getElementById("twitterStream").innerHTML = jsonObj[0].text;
}
}
}
}
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谢谢!