在Django的休息框架-simplejwt插件username和password默认情况下使用。但我想使用email而不是username. 所以,我确实喜欢以下内容:
在序列化器中:
class MyTokenObtainSerializer(Serializer):
username_field = User.EMAIL_FIELD
def __init__(self, *args, **kwargs):
super(MyTokenObtainSerializer, self).__init__(*args, **kwargs)
self.fields[self.username_field] = CharField()
self.fields['password'] = PasswordField()
def validate(self, attrs):
# self.user = authenticate(**{
# self.username_field: attrs[self.username_field],
# 'password': attrs['password'],
# })
self.user = User.objects.filter(email=attrs[self.username_field]).first()
print(self.user)
if not self.user:
raise ValidationError('The user is not valid.')
if self.user:
if not self.user.check_password(attrs['password']):
raise ValidationError('Incorrect credentials.')
print(self.user)
# Prior to Django 1.10, inactive users could be authenticated with the
# default …Run Code Online (Sandbox Code Playgroud) 我有这样一张桌子:
现在我想总结每个日期的饭菜.我写了下面的代码.但它并不像我想的那样有效.
模型:
class Meal(models.Model):
user = models.ForeignKey(settings.AUTH_USER_MODEL, default=1)
date_of_meal = models.DateField()
morning_meal = models.SmallIntegerField(default=0)
mid_day_meal = models.SmallIntegerField(default=0)
night_meal = models.SmallIntegerField(default=0)
updated = models.DateTimeField(auto_now=True, auto_now_add=False)
timestamp = models.DateTimeField(auto_now=False, auto_now_add=True)
class Meta:
ordering = ['-updated', '-timestamp']
def __str__(self):
return str(self.date_of_meal)
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码:
meals_list = Meal.objects.values('date_of_meal').annotate(mm=Sum('morning_meal'), mdm=Sum('mid_day_meal'), nm=Sum('night_meal'))
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输出:
<QuerySet [{'mdm': 0, 'mm': 1, 'date_of_meal': datetime.date(2017, 3,
23), 'nm':
1}, {'mdm': 1, 'mm': 1, 'date_of_meal': datetime.date(2017, 3, 23), 'nm': 0}, {
'mdm': 1, 'mm': 0, 'date_of_meal': datetime.date(2017, 3, 22), 'nm': 1}, {'mdm':
0, …Run Code Online (Sandbox Code Playgroud) 我收到以下错误。我已经在Google上进行了足够的搜索。但是没有什么可以解决我的问题。我的问题似乎与其他人不同。我正在使用BeautifulSoup。
我认为以下几行引起了问题。
soup = BeautifulSoup(req.content, 'html.parser').encode("utf-8")
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当我试图找到所有div有一个holder课时:
data = soup.find_all("div", {"class":"holder"})
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如果显示以下错误:
追溯(最近一次通话最近):文件“ web_crawler.py”,第32行,数据= soup.find_all(“ div”,{“ class”:“ holder”}))AttributeError:'bytes'对象没有属性'find_all '
是在encoding制造问题吗?
我Security在CakePHP 3.2中使用实用程序进行加密和解密.我打电话的时候
Security::encrypt('string', 'key') //密钥长度为32或更多
在字符串上的方法,它返回带有一些无效字符的加密字符串,如下所示:
8e88c050ff20cb12984bf1af24b11fc7ada198082c67d6b3da7170572d5bcd54plp21ķ;ܝ%N
我想用这个字符串url.但由于存在一些无效字符,因此无法正常工作.
现在我想避免这些角色.有没有办法避免这些角色?