小编Mar*_*k K的帖子

我使用下面的代码来获取网站的标题.

from bs4 import BeautifulSoup
import urllib2

line_in_list = ['www.dailynews.lk','www.elpais.com','www.dailynews.co.zw']

for websites in line_in_list:
    url = "http://" + websites
    page = urllib2.urlopen(url)
    soup = BeautifulSoup(page.read())
    site_title = soup.find_all("title")
    print site_title

如果网站列表包含"不良"(不存在)网站/网页,或者网站有某种类型或错误,例如"404找不到页面"等,则脚本将中断并停止.

我以什么方式让脚本忽略/跳过"坏"(不存在)和有问题的网站/网页？

在执行网络分析时，我想在地图上绘制网络图。ggmap 似乎是首选，但它需要 API 访问。

是否有任何不需要 API 访问的免费和等效/替代（到 ggmap）选项？

谢谢你。

如下所示的表格，我想从中创建一个新表格（使用“颜色”列中的值）。

我试过了：

import pandas as pd
import functools

data = {'Seller': ["Mike","Mike","Mike","Mike","David","David","Pete","Pete","Pete"], 
'Code' : ["9QBR1","9QBR1","9QBW2","9QBW2","9QD1X","9QD1X","9QEBO","9QEBO","9QEBO"],
'From': ["2020-01-03","2020-01-03","2020-01-03","2020-01-03","2020-01-03","2020-01-03","2020-01-03","2020-01-03","2020-01-03"],
'Color_date' : ["2020-02-14","2020-02-14","2020-05-18","2020-05-18","2020-01-04","2020-01-04","2020-03-04","2020-03-13","2020-01-28"],
'Color' : ["Blue","Red","Red","Grey","Red","Grey","Blue","Orange","Red"],
'Delivery' : ["Nancy","Nancy","Kate","Kate","Lilly","Lilly","John","John","John"]}

df = pd.DataFrame(data)

df_1 = df.set_index([df.index, 'Color'])['Color_date'].unstack()
df_1['Code'] = df['Code']

final_df = functools.reduce(lambda left,right: pd.merge(left,right,on='Code'), [df, df_1])

“df_1”看起来不错，但“final_df”比预期的要长得多。

哪里出错了，我该如何纠正？谢谢你。

有两个相应的1对1关系列表.

names = ["David", "Peter", "Kate", "Lucy", "Kit", "Jason", "Judy"]
scores = [1,1,0.8,0.2,0.4,0.1,0.6]

我想展示得分超过0.5并且显示在1行中的人:

Peter (1 point), David (1 point), Kate (0.8 point), Judy (0.6 point)

我尝试的是:

import operator

names = ["David", "Peter", "Kate", "Lucy", "Kit", "Jason", "Judy"]
scores = [1,1,0.8,0.2,0.4,0.1,0.6]

dictionary = dict(zip(names, scores))

dict_sorted = sorted(dictionary.items(), key=operator.itemgetter(1), reverse=True)

print dict_sorted

它给:

[('Peter', 1), ('David', 1), ('Kate', 0.8), ('Judy', 0.6), ('Kit', 0.4), ('Lucy', 0.2), ('Jason', 0.1)]

怎么能进一步得到想要的结果呢？注意:需要从大到小的排序结果.

2个用于测试目的的较长列表:

names = ["Olivia","Charlotte","Khaleesi","Cora","Isla","Isabella","Aurora","Amelia","Amara","Penelope","Audrey","Rose","Imogen","Alice","Evelyn","Ava","Irma","Ophelia","Violet"]
scores = [1.0, 1.0, 0.8, 0.2, 0.2, 0.4, …

我想过滤符合以下条件的行:

1. 字符'/'在行中
2. 人物';' 在线
3. 字符'e'在行中
4. 字符'k'不在行中
5. 字符'@'不在行中
6. 线的长度不超过80

我有的是:

the_list = ['C  TEE edBore 1 1/4200;',
'Cylinder SingleVerticalB HHJ e 1 1/8Cooling 1',
'EngineBore 11/1; TDT 8Length 3Width 3',
'EngineCy HEE Inline2008Bore 1',
'Height 4TheChallen TET e 1Stroke 1P 305',
'Height 8C ;0;Wall15ccG QBG ccGasEngineJ 142',
'Height EQE C ;0150ccGas2007',
'Length 10Wid ETQ Length 10Width ',
'Stro EHT oke 1 1/8Length ',
'Stroke 1 1/4HP   JII Stroke 1 1/4HP  ',
'Stroke 1Cy QTH 7Weight ; 1/2LBS',
'Weight 18LBSLength 1 DQT …

在Python 2.7.6中,列表如下.我以何种方式拿起物品以"4"开头,长度为4,即4646和4648以下？

aaa = [2013, 2014, 2002, 4646, 4648, 20, 456, 5623, 'abc']

我只能通过以下方式选择4个长度:

results = []

for number in aaa:
  if len(str(number)) == 4:
      results.append(number)

print results

谢谢.

一切都很棒.但我是新手,所以选择最简单的.:)