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如何基于Python中匹配的路径字符串创建列表?

我基本上试图将文件路径字符串分成同一路径中的文件列表.可以说我有这个清单:

files = ['user/hey.jpg','user/folder1/1.txt','user/folder1/folder2/random.txt',
         'user/folder1/blah.txt','user/folder3/folder4/folder5/1.txt',
         'user/folder3/folder4/folder5/3.txt','user/folder3/folder4/folder5/2.txt',
         'user/1.jpg']
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我想得到这个输出(不关心订单):

[
 ['user/folder1/1.txt','user/folder1/blah.txt']
 ['user/folder1/folder2/random.txt']
 ['user/folder3/folder4/folder5/1.txt',
  'user/folder3/folder4/folder5/2.txt','user/folder3/folder4/folder5/3.txt']
 ['user/1.jpg','user/hey.jpg']
]
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对不起,如果我的例子很草率.在手机上打字并不好玩.任何帮助表示赞赏!

python python-2.x python-2.7

2
推荐指数
1
解决办法
45
查看次数

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