$chow = 3;
echo ($chow == 1) ? "one" : ($chow == 2) ? "two" : "three";
输出:三
$chow = 1;
echo ($chow == 1) ? "one" : ($chow == 2) ? "two" : "three";
输出:两个
任何人都可以解释为什么当$ chow = 1而不是"one"时输出是"两个"？