我有很多脚本shell,我想在这个shell中包含一个包含变量的文件
脚本?
我的var脚本:
###################################################################################
ORACLE_LOGIN=login
ORACLE_PWD=pwd
CHEMIN_1="/home/"
CHEMIN_2="/scripts/"
LOG_FILE="$CHEMIN_1/max.log"
export ORACLE_SID=oracle_sid
###################################################################################
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我的脚本sh:
#!/bin/ksh
#set -x
# ============== LOAD VAR HERE ====================================
????
##################################################################
#### Begin ####
##################################################################
write "Begin $0"
$ORACLE_HOME/bin/sqlplus -s $ORACLE_LOGIN/$ORACLE_PWD@$ORACLE_SID <<EOF >> $LOG_FILE 2>&1
@$CHEMIN_2/sp_rep_alim_dia_date_max.sql
exit
EOF
write "End."
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谢谢.
我继续得到这个错误.有什么想法吗?
$ bower install ng-roundabout --save
bower cached git://github.com/angular/bower-angular-mocks.git#1.3.15
bower validate 1.3.15 against git://github.com/angular/bower-angular-mocks.
git#>=1.2.*
bower cached git://github.com/Wildhoney/ngRoundabout.git#0.2.5
bower validate 0.2.5 against git://github.com/Wildhoney/ngRoundabout.git#*
bower cached git://github.com/angular/bower-angular-mocks.git#1.2.28
bower validate 1.2.28 against git://github.com/angular/bower-angular-mocks.
git#~1.2.24
bower cached git://github.com/angular/bower-angular.git#1.2.28
bower validate 1.2.28 against git://github.com/angular/bower-angular.git#~1
.2.24
bower cached git://github.com/angular/bower-angular.git#1.3.15
bower validate 1.3.15 against git://github.com/angular/bower-angular.git#>=
1.2.0
bower cached git://github.com/angular/bower-angular.git#1.3.15
bower validate 1.3.15 against git://github.com/angular/bower-angular.git#>=
1.2.*
bower cached git://github.com/angular/bower-angular.git#1.3.15
bower validate 1.3.15 against git://github.com/angular/bower-angular.git#>=
1
bower cached git://github.com/angular/bower-angular.git#1.2.28
bower validate 1.2.28 against git://github.com/angular/bower-angular.git#1.
2.28
bower cached git://github.com/angular/bower-angular.git#1.3.15 …Run Code Online (Sandbox Code Playgroud) 我使用FileWriter创建一个文件.我有一个错误目录不存在我认为FileWriter创建目录,如果它不存在
FileWriter writer = new FileWriter(sFileName);
Run Code Online (Sandbox Code Playgroud) 我从Java导出到xls,我使用POI库.
我的createCell方法:
private Cell createCell(Row ligne, int col, String value, CellStyle style, HSSFWorkbook classeur) {
//org.apache.poi.hssf.usermodel.HSSFOptimiser.optimiseCellStyles(classeur);
CellStyle styleCell = classeur.createCellStyle();
styleCell.cloneStyleFrom(style);
return createCell(ligne, col, value, styleCell);
}
protected Cell createCell(Row ligne, int col, String value, CellStyle style) {
Cell cell = createCell(ligne, col, value);
cell.setCellStyle(style);
return cell;
}
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我在For中调用此方法,我有此消息错误:
Echec de l'export:超出了最大单元格样式数.您可以在.xls工作簿中定义最多4000个样式
如何重用我的单元格而不必重新创建每次迭代?
谢谢
我在以下问题中尝试过这个解决方案,但在我的情况下没有一个工作:
@Configuration
@EnableWebMvc
@ComponentScan("myapp.framework.export")
public class WebConfig extends MyAppWebConfig {
@Override
public void configureContentNegotiation(final ContentNegotiationConfigurer configurer) {
super.configureContentNegotiation(configurer);
}
@Override
public void configureMessageConverters(final List<HttpMessageConverter<?>> converters) {
super.configureMessageConverters(converters);
}
}
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错误:
INFO: Initializing Spring FrameworkServlet 'services-rest'
2017-04-11 15:25:52,774|localhost-startStop-1|NO_TID|NO_USER|ERROR|org.springframework.web.servlet.DispatcherServlet.initServletBean|Context initialization failed org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'xlsHttpMessageConverter': Injection of resource dependencies failed; nested exception is org.springframework.beans.factory.NoSuchBeanDefinitionException: No qualifying bean of type 'myapp.framework.export.ExportXlsModelService<?>[]' available: expected at least 1 bean which qualifies as autowire candidate. Dependency annotations: {@javax.annotation.Resource(shareable=true, lookup=, name=, description=, authenticationType=CONTAINER, type=class …Run Code Online (Sandbox Code Playgroud) 我想创建一个过程来检索我的表上的所有索引并重建
我使用此查询检索所有索引:
select index_name from user_indexes where table_name='your_table_name'
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我用这个查询重建:
alter index <index_name> rebuild;
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谢谢.
我想通过注释@Query通过Jpa存储库创建一个Join查询我有三个表.
本机查询是:
select application.APP_ID
from user, customer, application
where user.USE_CUSTOMER_ID = customer.CUS_ID
and application.APP_CUSTOMER_ID = customer.CUS_ID
and user.USE_ID=1;
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现在我有了Table Hibernate实体,所以我在ApplicationRepository中尝试过
@Query(SELECT application FROM Application a
INNER JOIN customer c ON c.customer.id = a.customer.id
INNER JOIN user u ON u.customer.id = c.customer.id
INNER JOIN application a ON a.user.id = u.id
WHERE
u.id = :user.id)
List<Application> findApplicationsByUser(@Param("User") User user);
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日志说
意外的标记
请问有什么想法吗?
我的表实体
Application.java:
@Entity
@Table
public class Application extends BaseSimpleEntity {
...
@ManyToOne(optional = false)
private Customer customer;
...
}
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Customer.java: …
我有一个String列表:
List<String> listString = new ArrayList<String>();
listString.add("faq");
listString.add("general");
listString.add("contact");
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我在列表上做了一些处理,我想对这个列表进行排序,但我希望"general"始终以第一个位置结束.谢谢 ;)
我有一个输入:
<div class="search-field search-field-date search-field-calendar ui-datepicker-calendar columns small-3">
<input type="text" data-ng-model="goDate"
placeholder="Date d'aller" data-mtx-datepicker data-mtx-maxdate="returnDate" data-mtx-time="horairesAller" />
</div>
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当我选择日期时,我有这个:

现在我想显示如下的多个信息:

当我选择日期时:

我不知道该怎么做.