考虑此代码(并使用SQLAlchemy 0.7.7):
class Document(Base):
__tablename__ = 'document'
__table_args__ = {
'schema': 'app'
}
id = Column(types.Integer, primary_key=True)
nom = Column(types.Unicode(256), nullable=False)
date = Column(types.Date())
type_document = Column(types.Enum('arrete', 'photographie',
name='TYPES_DOCUMENT_ENUM'))
__mapper_args__ = {'polymorphic_on': type_document}
class Arrete(Document):
__tablename__ = 'arrete'
__table_args__ = {
'schema': 'app'
}
__mapper_args__ = {'polymorphic_identity': 'arrete'}
id = Column(types.Integer, ForeignKey('app.document.id'), primary_key=True)
numero_arrete = Column(types.Integer)
date_arrete = Column(types.Date())
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我可以很容易地对Arrete类中定义的列的列类型进行内省:
Arrete.__table__.c['date_arrete'].type
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但是,如果我想通过Arrete类访问类中定义的列,则这不起作用Document.(如果我尝试访问,则为KeyError c['date']).
有没有办法获得列类型,无论列是在最终类中还是在其父类中定义的?
这不是一个问题,我只是想了解.考虑以下代码:
from sqlalchemy.ext.declarative import declarative_base
from sqlalchemy import *
from sqlalchemy.orm import sessionmaker, relationship
Base = declarative_base()
class AB(Base):
__tablename__= 'ab'
id_a = Column(Integer, ForeignKey('a.id', ondelete='CASCADE'), primary_key=True)
id_b = Column(Integer, ForeignKey('b.id', ondelete='CASCADE'), primary_key=True)
rel = Column(Unicode)
class A(Base):
__tablename__ = 'a'
id = Column(Integer, primary_key=True)
class B(Base):
__tablename__ = 'b'
id = Column(Integer, primary_key=True)
#1: doesn’t work try to set id_b to null
rel_a = relationship('AB')
# Works, but cascade='all' seems uneeded to me
rel_a = relationship('AB', cascade='all')
# Works …Run Code Online (Sandbox Code Playgroud) 尝试使用association_proxy时遇到错误.
我得到映射的类A,与B的0-n关系.B与C的0-n关系.association_proxy是从C访问A.
class C(base):
a = association_proxy('b', 'a')
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如果它确实与B有关系,它的工作没有问题.但如果这种关系是null,那么尝试访问myCinstance.a会抛出:AttributeError 'NoneType' object has no attribute 'a'.我猜它适用于1-n关系,但有没有一种方法myCinstance.a返回None而不是错误?(我看到了创建者选项,但看起来只是为了设置,而不是获取).
提前致谢.
我正在使用SqlAlchemy 0.7.5
编辑:我想出了一个简单的例子来描述问题https://gist.github.com/2225046