小编Joh*_*hnP的帖子

我有一个从XLS文件移植的数据库。我的电话号码是这种形式

3.41002E+13  

但是可读形式应为： 34100224263318

如何将第一种形式转换为第二种形式？

试图了解这个 isset($_POST) 代码在做什么

if (isset($_POST['Submit'])) {
    $title=$_POST['title'];
    $forename = $_POST['forename']; 
    $surname=$_POST['surname'];
    $dob=$_POST['dob'];
    $gender=$_POST['gender'];
    $email=$_POST['email']; 
    $phone=$_POST['phone'];
    $password=$_POST['password'];


    if (authRegister($title, $forename, $surname, $dob, $gender, $email, $phone, $password))
    {
        echo 'Thank you for registering your details, you can now login';           
    } 
    else
    {
        outputErrors();
    }

    $name = $_GET['fullname'];
    $phone = $_GET['phone'];
    $address = $_GET['address'];
    $size = $_GET['size'];
    $toppings = $_GET['toppings'];
    $delivery = $_GET['type'];



    mysql_connect ("localhost", "root", "") or die ('Error: ' . mysql_error());
    mysql_select_db ("pizzaorders");
    $query ="INSERT INTO orders (fullname, phone, address, size, toppings, delivery)  VALUES ('".$name."', '".$phone."', '".$address."','".$size."','".$toppings."','".$delivery.")";
    $done=mysql_query($query);
    echo $done;        

    $total = 0;
    $total = sizecost()  + deliverycost() + toppingcost();

    echo " $name  your {$_GET["size"]} pizza will come in 45 minutes.";
    echo "Total: $ $total";
    echo " Your Toppings are ";
    foreach($toppings as …

我有一个数组

$arrTest = array('val1','val2','val3','val4');
$arrTest['lastKey'] = 'Last Key';
foreach($arrTest as $key => $val) {
  if($key == 'lastKey') {
     echo "last found";
  }
}

上面的代码不起作用.我在数组中添加了关联元素.可能是原因吗？

我目前正在使用以下代码来执行此操作.

<span style="position: absolute; bottom: 0pt; right: 0pt;">
  Load time: 1.1920928955078E-5 seconds</span>

我遇到的问题是,如果页面是可滚动的,那么它就在页面的中间位置.我确信这有一个简单的解决方案,但我无法想出来.

任何帮助或建议将不胜感激.

为了在我点击的链接中找到类"imgBtn"(类 - "checkVacancy a"),我需要什么选择器？

      <div class="checkVacancy">
    <a rel="123">
        <img class="imgBtn" alt="" src="App_Themes/popup/bilder/btn_pruefen.png">
    </a>
    <div class="32531302a"></div>
  </div>
  <div class="checkVacancy">
    <a rel="123">
        <img class="imgBtn" alt="" src="App_Themes/popup/bilder/btn_pruefen.png">
    </a>
    <div class="32531302b"></div>
  </div>
  <div class="checkVacancy">
    <a rel="123">
        <img class="imgBtn" alt="" src="App_Themes/popup/bilder/btn_pruefen.png">
    </a>
    <div class="32531302c"></div>
  </div>

这是我使用的JS

   $(function(){
        $('.checkVacancy a').click(function() {

          //access only child image
          $('.imgBtn').attr('src','http://www.ajaxload.info/cache/9D/E5/1C/00/00/00/1-0.gif');                  

        });
    });

示例jsbin

我有这个JS系列我确定是错误的.

classes[i] = document.getElementsByAttribute ("class", show_hide_class_selectors[i]);

在上下文中

for (var i = 0; i< show_hide_class_selectors.length; i++) {
        classes[i] = document.getElementsByAttribute ("class", show_hide_class_selectors[i]);
        alert ("ok");
    }

有人能看出这是错的吗？

这是我的代码,我想计算这里的对象数量.

使用eval函数我能够获得元素,但不知道如何计算其中的总对象.有人可以帮帮我吗？

var txt = '{
    "employees": [{
        "a": "wkn",
        "d": "Wipro Technologies \u2013 IT Services, Product Engineering Solutions, Technology Infrastructure Services, Business Process Outsourcing, Consulting Services",
        "n": "",
        "u": "http://wipro.com/",
        "t": ["outsourcing", "offshore", "india"],
        "dt": "2009-06-26T10:26:02Z"
    }, {
        "a": "shaktimaan",
        "d": "Wipro Technologies \u2013 IT Services, Product Engineering Solutions, Technology Infrastructure Services, Business Process Outsourcing, Consulting Services",
        "n": "Wipro Technologies is the No 1 provider of integrated business, technology and process solutions on a global delivery platform.",
        "u": "http://wipro.com/", …

我只想返回用户表中的所有行,但选择的字段和可能的concat 2字段.

正常的sql可能刚刚:

SELECT id, CONCAT(`first_name`,`last_name`) AS `fullname` FROM `users`

但试图在蛋糕中实现这一点是一场噩梦:

$users = $this->User->find("all") = returns everything
$users = $this->User->find("list",array("fields" => " ...) does not work either.

任何人都可以帮助我如何使用蛋糕模型来实现简单的查询和返回结果

我有以下代码:

$(this).parent().find(".age").removeClass('active').children("input").prop('checked', false);
$(this).addClass('active').children('input').prop('checked', true); 

这有效,但我想缩小它并做这样的事情:

$(this).parent().find(".age").removeClass('active').children("input").prop('checked', false).find(this).addClass('active').children('input').prop('checked', true); 

或者

$(this).parent().find(".age").removeClass('active').children("input").prop('checked', false).children(this).addClass('active').children('input').prop('checked', true); 

这两个例子不起作用,但希望你能得到这个想法.