小编CJM*_*CJM的帖子

尝试检索具有超过 1 个副本的艺术家数量，我尝试使用以下 SQL，它返回错误。

ORA-00937: 不是单组组函数 00937。00000 - “不是单组组函数” *原因：*操作：行：22 列：8 处出错

SELECT W.WORKID,A.LASTNAME,A.FISRTNAME, COUNT(W.ARTISTID) AS Orders
FROM ( WORK W INNER JOIN ARTIST A
ON W.ARTISTID=A.ARTISTID)
GROUP BY A.LASTNAME, W.WORKID, A.FISRTNAME
HAVING COUNT (W.ARTISTID) > 1;

SELECT WORKID,LASTNAME,FIRSTNAME
FROM WORK W, ARTIST A
WHERE W.ARTISTID = A.ARTISTID
HAVING COUNT (W.ARTISTID) > 1;

我正在尝试解析节点js中的url。从此代码中获取空值。它正在接收路径的值。但不适用于主机或协议。

var http = require('http');
var url = require('url');
http.createServer ( function (req,res){
    var pathname = url.parse(req.url).pathname;
    var protocol = url.parse(req.url).protocol;
    var host = url.parse(req.url).host;
    console.log("request for " + pathname + " recived.");
    console.log("request for " + protocol + " recived.");
    console.log("request for " + host + " recived.");
    res.writeHead(200,{'Content-Type' : 'text/plain'});
    res.write('Hello Client');
    res.end();
 }).listen(41742);
 console.log('Server Running at port 41742');
 console.log('Process IS :',process.pid);

我需要在C#中打印这样的风格

*****
 ***
  *

我怎么能这样做？

到目前为止,我得到了以下代码,但它以另一种方式打印并减少了一颗星.

int number = 5;
int i, j, k;
for (i = 1; i <= number; i++)
{
    for (j = 1; j <= number - i; j++)
    {                    
        Console.Write("");
    }

    for (k = 1; k <= i; k++)
    {
        Console.Write("*");
    }

    Console.WriteLine("");
}