我想将文本框中的数据插入到oracle数据库中,所以在我的HTML中有文本框(和3个按钮 - 新建,更新并保存)所以当我点击三个按钮中的任何一个时,我需要redirectServlet,并从这个servlet我想再次将我的页面转发到insertServlet(即当我点击NEW按钮时),但我收到404错误.可能是我的逻辑错误或wex.xml需要正确映射.任何人都可以帮助请它紧急.
**wex.xml code**
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
<display-name>AcerLink</display-name>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
</welcome-file-list>
<servlet>
<display-name>redirectServlet</display-name>
<servlet-name>redirectServlet</servlet-name>
<servlet-class>redirectServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>redirectServlet</servlet-name>
<url-pattern>/redirectServlet</url-pattern>
</servlet-mapping>
<servlet>
<description></description>
<display-name>insertServlet</display-name>
<servlet-name>insertServlet</servlet-name>
<servlet-class>insertServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>insertServlet</servlet-name>
<url-pattern>/insertServlet</url-pattern>
</servlet-mapping>
</web-app>
Run Code Online (Sandbox Code Playgroud)
redirectServlet
import java.io.IOException;
import java.io.PrintWriter;
import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.SQLException;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
/**
* Servlet implementation class redirectServlet
*/
public class redirectServlet extends HttpServlet {
private static final …Run Code Online (Sandbox Code Playgroud)