小编map*_*008的帖子

在使用Laravel 5.2过滤器时遇到问题,过滤后,我得到了一些意想不到的键,如"0","1","2"......,我该如何删除它？

过滤前:

[
  {
    "id": 1,
    "user_id": 11,
    "location": "1",
    "content": "1",
    "interest_id": 1,
    "longitude": 1,
    "latitude": 1,
    "place_id": "1",
    "created_at": "2016-06-09 15:44:18",
    "updated_at": "2016-06-02 14:28:42",
    "deleted_at": null
  },
  {
    "id": 2,
    "user_id": 12,
    "location": "Forest Lake QLD, Australia",
    "content": "I'm newbie. Hello everybody",
    "interest_id": 1,
    "longitude": 152.9692508,
    "latitude": -27.6236519,
    "place_id": "ChIJB_NHl8hOkWsRMIne81qjAgU",
    "created_at": "2016-06-09 14:28:42",
    "updated_at": "2016-06-09 14:28:42",
    "deleted_at": null
  },
  {
    "id": 8,
    "user_id": 11,
    "location": "Hendra QLD, Australia",
    "content": "What time is it?",
    "interest_id": 1,
    "longitude": 153.0635202, …

我想传递一个接口作为参数,如下所示:

class Test {
    fun main() {
        test({})
        // how can I pass here?
    }

    fun test(handler: Handler) {
        // do something
    }

    interface Handler {
        fun onCompleted()
    }
}

在Java中,我可以使用匿名函数test(new Handler() { .......... }),但我不能在Kotlin中执行此操作.有人知道怎么做吗？

java.io.IOException: Cannot run program "yarn": error=2, No such file or directory
    at java.lang.ProcessBuilder.start(ProcessBuilder.java:1048)
    at java.lang.Runtime.exec(Runtime.java:620)
    at java.lang.Runtime.exec(Runtime.java:450)
    at java.lang.Runtime.exec(Runtime.java:347)
    at com.Main.main(Main.java:32)

你好，我在使用 Java 执行命令时遇到了一个奇怪的问题。我使用以下代码来运行命令，如果我运行mkdir testFolder，则程序运行成功，但如果我更改命令，yarn -v 则会发生错误。

try {
    Process process = Runtime.getRuntime().exec("yarn -v");//, null, new File("/Users/macos/Desktop/TestProj/"));
} catch (IOException ex) {
    ex.printStackTrace();
}

P/s: 在调试模式下：IntelliJ 可以运行上面的代码，但 Netbeans 失败。

在生产模式下（jar 文件）：IntelliJ 也失败了。

编辑2：

  MACs-MacBook-Pro:~ macos$ which pwd
    /bin/pwd
    MACs-MacBook-Pro:~ macos$ which mkdir
    /bin/mkdir
    MACs-MacBook-Pro:~ macos$ which java
    /usr/bin/java
    MACs-MacBook-Pro:~ macos$ which yarn
    /usr/local/bin/yarn

/bin我发现如果我运行or中的命令/usr/bin，代码运行正常（pwd，mkdir，java …

将八进制数转换为字符串时遇到问题.

p = 01212
k = str(p)
print k

结果是650但我需要01212.我怎样才能做到这一点？提前致谢.

我使用过Firebase Dynamics链接,它可以打开我的应用,去玩商店或转到网址.但是当我通过链接传递一些参数时,我只能得到第一个参数.这是我的动态链接:

https://xx.app.goo.gl/?link=http://xx.com/?usn=abc&pass=def&apn=com.xx&afl=http://google.com

我使用此代码获取链接:

// Build GoogleApiClient with AppInvite API for receiving deep links
        mGoogleApiClient = new GoogleApiClient.Builder(this)
                .enableAutoManage(this, this)
                .addApi(AppInvite.API)
                .build();

        // Check if this app was launched from a deep link. Setting autoLaunchDeepLink to true
        // would automatically launch the deep link if one is found.
        boolean autoLaunchDeepLink = false;
        AppInvite.AppInviteApi.getInvitation(mGoogleApiClient, this, autoLaunchDeepLink)
                .setResultCallback(
                        result -> {
                            if (result.getStatus().isSuccess()) {
                                // Extract deep link from Intent
                                Intent intent = result.getInvitationIntent();
                                String deepLink = AppInviteReferral.getDeepLink(intent);
                                Logger.e(deepLink);
                            }
                        }
                ); …

我只是按照本教程通过面容 ID 对用户进行身份验证，但实际上在身份验证失败后，它不适用于“再次尝试面容 ID”按钮，没有调用回调，我不知道为什么。这是代码：

@IBAction func touchIdAction(_ sender: UIButton) {

    print("hello there!.. You have clicked the touch ID")

    let myContext = LAContext()
    let myLocalizedReasonString = "Biometric Authntication testing !! "

    var authError: NSError?
    if #available(iOS 8.0, macOS 10.12.1, *) {
        if myContext.canEvaluatePolicy(.deviceOwnerAuthenticationWithBiometrics, error: &authError) {
            myContext.evaluatePolicy(.deviceOwnerAuthenticationWithBiometrics, localizedReason: myLocalizedReasonString) { success, evaluateError in

                DispatchQueue.main.async {
                    if success {
                        // User authenticated successfully, take appropriate action
                        self.successLabel.text = "Awesome!!... User authenticated successfully"
                    } else {
                        // User did not authenticate successfully, look …