在python中python中的dir()函数和__dir__属性有什么区别?
>>> 2 .__dir__()
['__divmod__', 'real', '__rxor__', '__floor__', '__hash__', '__index__', '__lt__', '__ceil__', '__repr__', '__reduce_ex__', '__rpow__', '__rand__', '__truediv__', '__subclasshook__', '__doc__', '__radd__', '__or__', '__pow__', '__trunc__', '__rrshift__', '__delattr__', '__reduce__', '__rlshift__', 'conjugate', '__xor__', '__rtruediv__', '__rfloordiv__', '__ge__', '__setattr__', '__class__', 'bit_length', '__neg__', '__mod__', '__int__', '__pos__', 'from_bytes', '__format__', '__rmul__', '__lshift__', '__rsub__', '__new__', '__add__', '__floordiv__', 'imag', 'to_bytes', 'numerator', '__dir__', '__abs__', '__init__', '__sizeof__', '__getnewargs__', '__getattribute__', '__invert__', '__gt__', '__rshift__', '__ne__', '__rdivmod__', '__mul__', '__and__', '__sub__', '__rmod__', '__round__', '__ror__', '__le__', '__eq__', '__float__', '__bool__', '__str__', 'denominator']
>>> dir(2)
['__abs__', …Run Code Online (Sandbox Code Playgroud) 在microsoft Identity 2中有能力用户可以确认我在这个项目中从这里下载了Identity 2示例项目的电子邮件地址没有任何区别用户确认了他们的电子邮件和谁没有我想要的人如何不确认他们的电子邮件无法登录这是我试过的:
public async Task<ActionResult> Login(LoginViewModel model, string returnUrl)
{
if (!ModelState.IsValid)
{
return View(model);
}
var result = await SignInManager.PasswordSignInAsync(model.Email, model.Password, model.RememberMe, shouldLockout: true);
switch (result)
{
case SignInStatus.Success:
{
var user = await UserManager.FindByNameAsync(model.Email);
if (user != null)
{
if (!await UserManager.IsEmailConfirmedAsync(user.Id))
{
//first I tried this.
//return LogOff();
HttpContext.Server.TransferRequest("~/Account/LogOff");
return RedirectToAction("Login");
}
}
return RedirectToLocal(returnUrl);
}
case SignInStatus.LockedOut:
return View("Lockout");
case SignInStatus.RequiresVerification:
return RedirectToAction("SendCode", new { ReturnUrl = returnUrl });
case SignInStatus.Failure:
default: …Run Code Online (Sandbox Code Playgroud) 因为我发现Lucene.Net.Linq最近更新相对于LinqToLucene并且它在nuget中可用我想在我的简单项目中使用它,但我遇到了缺少文档而我找不到如何使用lucene使用此包的高级查询,例如LinqToLucene中可能的查询:
var query = from c in index.Customers
where c.Like("amber") || c.CompanyName.Between("a", "d")
where !c.CustomerId == "Jason"
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如果这个扩展功能不可用那么这个项目有什么意义呢?
我有一个字符串,其中包含一个以十六进制形式的SHA256摘要,如blow:
"257612236efae809c23330ab67cf61f73aec938503f3ce126c34c6a32059f5f0"
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我想将其转换hash.digest()为如下所示:
b'%v\x12#n\xfa\xe8\t\xc230\xabg\xcfa\xf7:\xec\x93\x85\x03\xf3\xce\x12l4\xc6\xa3 Y\xf5\xf0'
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我该如何实现?我用Crypto.Hash和python 3.3.2
我想用RSA公钥解密一条消息,PyCrypto我正在使用下面的代码,但是no private key在下面的代码中应该改变错误?
from Crypto.PublicKey import RSA
from Crypto.Cipher import PKCS1_OAEP
import base64
licence_key="bla bla"
licence_key_in_bytes=licence_key.encode("utf-8")
encrypted=base64.b16decode(licence_key_in_bytes)
key = open("public_key", "r").read()
rsakey = RSA.importKey(key)
rsakey = PKCS1_OAEP.new(rsakey)
decrypted_message= rsakey.decrypt(encrypted)
Run Code Online (Sandbox Code Playgroud) 关闭应用程序时,以下示例代码与此错误崩溃:
QBasicTimer::start: QBasicTimer can only be used with threads started with QThread
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这是我的代码:
import sys
from PyQt4 import QtGui ,QtCore
app = QtGui.QApplication(sys.argv)
data=[]
data.append("one")
model=QtGui.QStringListModel(data)
combobox=QtGui.QComboBox()
combobox.show()
combobox.setModel(model)
sys.exit(app.exec_())
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我发现这是关于使用模型,但我不知道如何解决它.
编辑:os:win 7 64bit pyqt4
这怎么可能endIndex和count一个String在swift2不同?它是我用过的代码示例.当所有字符都只是英文时,它不会发生.
print("count:",self.Label.text!.characters.count)
print("endIndex:",self.Label.text!.characters.endIndex)
print("String:",self.Label.text!)
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输出:
count: 32
endIndex: 34
String: • (????? ????) ????????? ?????????
Run Code Online (Sandbox Code Playgroud) python ×5
pycrypto ×2
asp.net-mvc ×1
pyqt ×1
python-3.x ×1
qcombobox ×1
rsa ×1
swift ×1
swift2 ×1
windows ×1