小编cpp*_*hex的帖子

根据C++ 11规则,默认情况下会生成6个内容(默认构造函数,复制构造函数,移动构造函数,复制赋值,移动赋值和析构函数).根据第二个规则,当定义任何自定义副本,移动或析构函数时,不会生成这些默认操作.但是在我之后的代码中并非如此.但是这段代码无法编译错误

call to implicitly deleted copy constructor of 'Uni'

当我为Uni编写自己的复制构造函数时,一切正常.(在代码中注释,供参考)

任何想法都非常感激.

最后,我在Mac上运行它,使用LLVM编译器运行Xcode.

非常感谢...

#include <iostream>

class A
{
public:
    A(int i) :num{i}
    {
        std::clog<< "ctor  A() num = " << num << "\n";

    }
    A( A const &aRef)
    :num{aRef.num}
    {
        std::clog << " copy ctor A( A const &aRef) num = " << num << "\n";
    }

    int value()
    {
        return num;
    }

private:
    int num;

};
class Uni
{

public:
    Uni(A* aptr) : up{aptr}
    {
        std::clog << " …

为什么动态创建线程向量是错误的？我收到编译错误

C:\Program Files (x86)\Microsoft Visual Studio 12.0\VC\include\xmemory0(593)：错误 C2280：'std::thread::thread(const std::thread &)'：试图引用已删除的函数

其次是很多其他的东西。

#include <iostream>
#include <thread>
#include <vector>

using std::vector;
using std::thread;
using std::cout;

class obj_on_thread {
public:
    void operator()()
    {
        std::cout << "obj on thread\n";
    }
};

void function_on_thread() {
    std::cout << "function on thread\n";
}

auto named_lambda = []() { std::cout << "named_lambda_on_thread\n"; };

int main(){
    obj_on_thread obj;

    vector<thread> pool {
        thread{ obj },
        thread{ function_on_thread },
        thread{ named_lambda },
        thread{ []() { cout << "anonymous lambda on thread\n"; …