小编whi*_*732的帖子

尝试编写一些将加密或解密文件的函数,并使用此处的类来尝试实现此目的:

http://www.itnewb.com/v/PHP-Encryption-Decryption-Using-the-MCrypt-Library-libmcrypt

下面的加密函数似乎有效,因为它似乎加密文件并将其放在目标目录中.我现在正试图解密该文件,它只是死于"无法完成解密"的消息(在那里编码...)在php错误日志中没有任何内容,所以我不确定它为什么会失败,但由于mcrypt对我来说是全新的,我更倾向于相信我在这里做错了...

以下是功能:

//ENCRYPT FILE
    function encryptFile() {
        global $cryptastic;
        $pass = PGPPASS;
        $salt = PGPSALT;
        $key = $cryptastic->pbkdf2($pass, $salt, 1000, 32) or die("Failed to generate secret key.");

        if ($handle = opendir(PATH.'/ftpd')) {
            while (false !== ($file = readdir($handle))) {
                if ($file != "." && $file != "..") {
                    $newfile = PATH.'/encrypted/'.$file.'.txt';
                    $msg = file_get_contents(PATH.'/ftpd/'.$file);
                    $encrypted = $cryptastic->encrypt($msg, $key) or die("Failed to complete encryption.");
                    $nfile = fopen($newfile, 'w');
                    fwrite($nfile, $encrypted);
                    fclose($nfile);
                    unlink(PATH.'/ftpd/'.$file);

                }
            }
            closedir($handle);
        }       


//DECRYPT FILE
    function …

我正在尝试编写一个从FTP服务器下载文件的脚本.它们都相当大(每个近2GB).该脚本开始运行,但最终会因上述错误而终止.尺寸有关吗？有没有解决的办法？这是代码:

<?php

$ftp_server = "ftp.EXAMPLE.com";
$conn_id = ftp_connect ($ftp_server) or die("Couldn't connect to $ftp_server");
$login_result = ftp_login($conn_id, "USERNAME", "PASSWORD");
if ((!$conn_id) || (!$login_result)) die("FTP Connection Failed");
ftp_sync("download");   
ftp_close($conn_id); 

$mkdir = date('Y-m-d');
mkdir('encrypted/'.$mkdir, 0777);
smartCopy("./download/", 'encrypted/'.$mkdir);
chmodr("encrypted/".$mkdir, 0777);

function ftp_sync ($dir) {

    global $conn_id;

    if ($dir != ".") {
        if (ftp_chdir($conn_id, $dir) == false) {
            echo ("Change Dir Failed: $dir<BR>\r\n");
            return;
        }
        if (!(is_dir($dir)))
            mkdir($dir);
        chdir ($dir);
    }

    $contents = ftp_nlist($conn_id, ".");
    foreach ($contents as $file) {

        if ($file == '.' …

试图创建一个背景图片幻灯片,并收到此错误...这是我正在尝试实现的代码:

var $j = jQuery.noConflict();
$j( function(){
    var bgArr = [ 'sample1.jpg','sample2.jpg','sample3.jpg' ];
    function backgroundSlide(i) {
             $j("#home_sub_banner").css("background-image", "url("+bgArr[i++]+")");
             if (i == bgArr.length) i = 0;
             var st = setTimeout(arguments.callee(i), 1000);
    }
backgroundSlide(0)

});