我有一个表阿与绳柱一和表乙与串列b.a是b的子串.现在我想加入a和b上的两个表.这可能吗?
我想要这样的东西:
Select * from A,B where A.a *"is substring of"* B.b
如何在SQL(Transact-SQL)中编写它?
我使用的是weblogic JDBC数据源,我的数据库是Oracle 10g,下面是配置.
它过去工作正常,但突然它开始给出问题,请看下面的例外.
Weblogic JDBC数据源,java.sql.SQLException:无法获取XAConnection weblogic.common.resourcepool.ResourceLimitException:池中当前没有可用的资源
Run Code Online (Sandbox Code Playgroud)<?xml version="1.0" encoding="UTF-8"?> <jdbc-data-sourcexmlns ="http://www.bea.com/ns/weblogic/90"xmlns:sec ="http://www.bea.com/ns/weblogic/90/security"xmlns:wls ="http:/ /www.bea.com/ns/weblogic/90/security/wls"xmlns:xsi ="http://www.w3.org/2001/XMLSchema-instance"xsi:schemaLocation ="http://www.bea .com/ns/weblogic/920 http://www.bea.com/ns/weblogic/920.xsd "> XL-Reference-DS
jdbc:oracle:oci:@ abc.COM oracle.jdbc.driver.OracleDriver user DEV_260908密码密码dll ocijdbc10协议oci oracle.jdbc.V8Compatible true baseDriverClass oracle.jdbc.driver.OracleDriver
1 100 1 true SQL SELECT 1 FROM DUAL
DataJndi OnePhaseCommit
此异常发生在dev环境中,其中连接的用户只有一个.
我知道这与池最大大小有关,但我也怀疑这可能是由于Oracle,可能是Oracle无法创建连接.
我的问题:
Diagnosis.erb文件中的奇怪错误_set_controller_content_type.
请帮忙.
NoMethodError in Timelines#public_timeline
Showing /opt/local/lib/ruby1.9/gems/1.9.1/gems/actionpack-2.3.5/lib/action_controller/templates/rescues/diagnostics.erb where line # raised:
undefined method `content_type' for nil:NilClass
Extracted source (around line #):
RAILS_ROOT: /Volumes/DATA/Source/Rails/tvider
Application Trace | Framework Trace | Full Trace
/opt/local/lib/ruby1.9/gems/1.9.1/gems/activesupport-2.3.5/lib/active_support/whiny_nil.rb:52:in `method_missing'
/opt/local/lib/ruby1.9/gems/1.9.1/gems/actionpack-2.3.5/lib/action_view/base.rb:331:in `_set_controller_content_type'
/opt/local/lib/ruby1.9/gems/1.9.1/gems/actionpack-2.3.5/lib/action_view/renderable.rb:32:in `block in render'
/opt/local/lib/ruby1.9/gems/1.9.1/gems/actionpack-2.3.5/lib/action_view/base.rb:306:in `with_template'
/opt/local/lib/ruby1.9/gems/1.9.1/gems/actionpack-2.3.5/lib/action_view/renderable.rb:30:in `render'
/opt/local/lib/ruby1.9/gems/1.9.1/gems/actionpack-2.3.5/lib/action_view/template.rb:205:in `render_template'
/opt/local/lib/ruby1.9/gems/1.9.1/gems/actionpack-2.3.5/lib/action_view/base.rb:265:in `render'
/opt/local/lib/ruby1.9/gems/1.9.1/gems/actionpack-2.3.5/lib/action_controller/rescue.rb:134:in `rescue_action_locally'
/opt/local/lib/ruby1.9/gems/1.9.1/gems/actionpack-2.3.5/lib/action_controller/rescue.rb:152:in `rescue_action_without_handler'
/opt/local/lib/ruby1.9/gems/1.9.1/gems/actionpack-2.3.5/lib/action_controller/rescue.rb:74:in `rescue_action'
/opt/local/lib/ruby1.9/gems/1.9.1/gems/actionpack-2.3.5/lib/action_controller/rescue.rb:162:in `rescue in perform_action_with_rescue'
/opt/local/lib/ruby1.9/gems/1.9.1/gems/actionpack-2.3.5/lib/action_controller/rescue.rb:160:in `perform_action_with_rescue'
/opt/local/lib/ruby1.9/gems/1.9.1/gems/actionpack-2.3.5/lib/action_controller/flash.rb:146:in `perform_action_with_flash'
/opt/local/lib/ruby1.9/gems/1.9.1/gems/actionpack-2.3.5/lib/action_controller/base.rb:532:in `process'
/opt/local/lib/ruby1.9/gems/1.9.1/gems/actionpack-2.3.5/lib/action_controller/filters.rb:606:in `process_with_filters'
/opt/local/lib/ruby1.9/gems/1.9.1/gems/actionpack-2.3.5/lib/action_controller/base.rb:391:in `process'
/opt/local/lib/ruby1.9/gems/1.9.1/gems/actionpack-2.3.5/lib/action_controller/base.rb:386:in `call'
/opt/local/lib/ruby1.9/gems/1.9.1/gems/actionpack-2.3.5/lib/action_controller/routing/route_set.rb:437:in `call'
Request
Parameters:
None
Show session dump
Response …Run Code Online (Sandbox Code Playgroud) 我views.py在 django 应用程序中创建了一个类视图。
class HelloTemplate(TemplateView):
template_name = "index.html"
def get_context_data(self, **kwargs):
context = super(HelloTemplate, self).get_context_data(**kwargs)
return context
Run Code Online (Sandbox Code Playgroud)
现在我在 html 页面中定义了一个表单:
<form method="get">
<input type="text" name="q">
<input type="text" name="q1">
<input type="submit" value="Search">
</form>
Run Code Online (Sandbox Code Playgroud)
如您所见,我form在同一页面上提交。
现在我想在我的HelloTemplate班级中获取表单提交的值。我不想在现有类之外创建另一个类或方法。
另外,如果未在 django 中验证数据,我想向 html 表单发送错误消息。
我不知道如何做到这一点,请帮助我。
我需要像SomethingModel.objects.all()这样的所有对象.
class SometingModel(model.Model):
def get_all_objects(self):
__[what should i do?]__
return queryset
Run Code Online (Sandbox Code Playgroud)
例如,
queryset = SomethingModel.objects.all()
queryset_by_instance = SomethingModel.objects.get(pk=1).get_all_objects()
queryset == queryset_by_instance <===== True {doesn't matter order}
Run Code Online (Sandbox Code Playgroud)
我需要这个来进行数据提取.喜欢
def get_filtered_data(object, object_attribute, min, max):
return object.get_all_objects().filter(object_attribute__lte=max)\
.filter(object_attribute__gte=min)
Run Code Online (Sandbox Code Playgroud) 我可以通过调用其.Copy方法来复制工作表。
Sheets("Example").Copy After:=Worksheets("Sheet3")
Run Code Online (Sandbox Code Playgroud)
但是,这还会复制与该工作表关联的所有宏或事件处理程序。如何在不复制任何Visual Basic代码的情况下复制工作表?
在我的情况下,我希望挑选(使用pickle.dump())两个单独的列表到一个文件,然后从一个单独的文件中检索这些,但是当使用时pickle.load()我一直在努力寻找一个列表结束的地方,而下一个列表开始,因为我根本不知道如何pickle.dump()即使在查看文档之后,它们也能够轻松检索.
我需要在python中测试一个函数,该函数接受具有任何类型的数据的列表,从整数到字符串再到用户组成的任何对象。假设中是否有一种方法可以生成带有随机对象的列表?我知道我可以使用生成随机浮动列表
@given(strategies.lists(strategies.floats()))
Run Code Online (Sandbox Code Playgroud)
等等,包括整数,字符等。但是,如何使它成为随机列表却具有多个数据类型呢?
我正在尝试使用木薯将 csv 转换为向量。我尝试转换的 csv 是用于机器学习的 fischer iris 数据集。它由四个双打和一根弦组成。我的代码如下:
{-# LANGUAGE OverloadedStrings #-}
module Main where
import Data.Csv
import qualified Data.ByteString.Lazy as BS
import qualified Data.Vector as V
data Iris = Iris
{ sepal_length :: !Double
, sepal_width :: !Double
, petal_length :: !Double
, petal_width :: !Double
, iris_type :: !String
} deriving (Show, Eq, Read)
instance FromNamedRecord Iris where
parseNamedRecord r =
Iris
<$> r .: "sepal_length"
<*> r .: "sepal_width"
<*> r .: "petal_length"
<*> r .: "petal_width" …Run Code Online (Sandbox Code Playgroud) 我眼前的问题是从API获取数据并将数据输入到csv中。我能够获取数据,但是将数据输出到csv是我遇到错误的地方。有人可以帮忙吗?
这是示例代码:
import csv,sys
def read_campaign_info(campaigns):
myfile = csv.writer(open("output.csv", "w"))
for insight in reach_insights:
account_id = str(insight[AdsInsights.Field.account_id])
objective = str(insight[AdsInsights.Field.objective])
metrics =[account_id,objective]
wr = csv.writer(myfile,quoting=csv.QUOTE_ALL)
wr.writerows(metrics)
Run Code Online (Sandbox Code Playgroud)
变量类型metrics为<class 'list'>
我得到的错误是
wr = csv.writer(myfile,quoting=csv.QUOTE_ALL)
TypeError: argument 1 must have a "write" method
Run Code Online (Sandbox Code Playgroud) python ×5
csv ×2
django ×2
datasource ×1
django-forms ×1
excel ×1
excel-vba ×1
haskell ×1
html ×1
parsing ×1
pickle ×1
python-3.x ×1
sql ×1
sql-server ×1
t-sql ×1
testing ×1
vba ×1
weblogic ×1