我在运行grails s2-quickstart com.testApplication.secureApplication User Role后自动生成我所做的域对象时grails run-app,从grails插件页面安装了spring security app,并得到了以下异常:
|Loading Grails 2.3.4
|Configuring classpath
.
|Environment set to development
.................................
|Packaging Grails application
Precompiling AST Transformations ...
src C:\Users\GrailsWorkspace\testApplication\target\work\plugins\postgresql-extensions-0.6.1 C:\Users\GrailsWorkspace\testApplication\target\classes
Done precompiling AST Transformations!
..
|Compiling 3 source files
...................................................
|Running Grails application
Configuring Spring Security Core ...
... finished configuring Spring Security Core
Error |
2013-12-15 15:42:45,635 [localhost-startStop-1] ERROR hbm2ddl.SchemaExport - Unsuccessful: create table user (id int8 not null, version int8 not null, account_expired bool not …Run Code Online (Sandbox Code Playgroud) 我在我的项目中遇到以下异常:
管理类"com.testApp.domain.Register",但未在persistence.xml文件中列出
我的persistence.xml文件看起来像这样:
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.0"
xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name="default" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<properties>
<property name="hibernate.archive.detection" value="class, hbm" />
<property name="hibernate.show_sql" value="true" />
<property name="hibernate.format_sql" value="true" />
<property name="hibernate.dialect" value="org.hibernate.dialect.PostgreSQLDialect" />
<property name="hibernate.hbm2ddl.auto" value="update" />
<property name="hibernate.connection.driver_class" value="org.hsqldb.jdbcDriver" />
<property name="hibernate.connection.url" value="jdbc:hsqldb:mem:." />
<property name="hibernate.connection.username" value="SA" />
<property name="hibernate.connection.password" value="" />
<property name="hibernate.c3p0.min_size" value="5" />
<property name="hibernate.c3p0.max_size" value="20" />
<property name="hibernate.c3p0.timeout" value="300" />
<property name="hibernate.c3p0.max_statements" value="50" />
<property name="hibernate.c3p0.idle_test_period" value="3000" />
</properties>
</persistence-unit>
</persistence>
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我已经尝试过这篇 …
我使用grails 2.3.4 用eclipse grails plugin(GGTS).但是,安装完成后我创建了一个项目并得到:
Description Resource Path Location Type
Groovy: compiler mismatch Project level is: 2.1 Workspace level is 1.8
Groovy compiler level expected by the project does not match workspace compiler level.
Go to Project properties -> Groovy compiler to set the Groovy compiler level for this project test test Groovy compiler mismatch problem
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我试图更改编译器首选项但没有任何变化......

我非常感谢你的回答!
我必须从oracle 11db 查询.通过下面的查询,我TAG_VALUE, TAG_DESC, INSERTION_DATE and PROJECT_ID从我的数据库中获取最新信息.
SELECT *
FROM (SELECT t.tag_value,
t.tag_desc,
u.update_as_of AS INSERTION_DATE,
p.proj_id AS PROJECT_ID,
Row_number()
over(
PARTITION BY p.proj_id
ORDER BY u.update_as_of DESC) RN
FROM project p
join update u
ON p.project_id = u.project_id
join tag t
ON t.tag_id = u.tag_id
WHERE t.tag_desc LIKE 'Equity%')
WHERE rn = 1;
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但是,我遇到的情况是,我的请求的答案(没有按日期排序)看起来像这样:
+----------------------------------------------+
| TAG_VALUE TAG_DESC INSERTION_DATE PROJECT_ID |
+----------------------------------------------+
| null Equity 14-DEC-14 1 |
| 0 Equity 14-DEC-14 1 |
| …Run Code Online (Sandbox Code Playgroud) 我想通过 Composer 在我的新 Laravel 4.2 安装上安装一些软件包。但是,我得到了一个例外。
这是我的作曲家文件:
{
"name": "laravel/laravel",
"description": "The Laravel Framework.",
"keywords": ["framework", "laravel"],
"license": "MIT",
"license": "MIT",
"require": {
"laravel/framework": "4.2.*",
"zizaco/confide": "~4.0@dev",
"zizaco/entrust": "1.2.*@dev",
"barryvdh/laravel-ide-helper": "1.*",
"fzaninotto/faker": "1.3.*@dev",
"bllim/datatables": "~1.3",
"barryvdh/laravel-debugbar": "~1.7"
},
"require-dev": {
"way/generators": "~2.6",
"barryvdh/laravel-ide-helper": "~1.11"
},
"autoload": {
"classmap": [
"app/commands",
"app/controllers",
"app/models",
"app/database/migrations",
"app/database/seeds",
"app/tests/TestCase.php",
"app/controllers/admin",
"app/controllers/user"
]
},
"scripts": {
"post-install-cmd": [
"php artisan clear-compiled",
"php artisan optimize"
],
"post-update-cmd": [
"php artisan clear-compiled",
"php artisan optimize"
],
"post-update-cmd":[ …Run Code Online (Sandbox Code Playgroud) 我试图在云9环境中安装python.
我在下面简单介绍一下,从安装教程:
pip install zipline
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但是,我得到:
Command python setup.py egg_info failed with error code 1 in /tmp/pip_build_ubuntu/zipline
Storing debug log for failure in /home/ubuntu/.pip/pip.log
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我的完整日志如下所示:
------------------------------------------------------------
/usr/bin/pip run on Tue Sep 13 06:28:52 2016
Downloading/unpacking zipline
Getting page https://pypi.python.org/simple/zipline/
URLs to search for versions for zipline:
* https://pypi.python.org/simple/zipline/
Analyzing links from page https://pypi.python.org/simple/zipline/
Found link https://pypi.python.org/packages/06/8e/8355df80f313706418ee9db3521c6f0578426d92b6dcddf396d58c4de2e6/zipline-1.0.2.tar.gz#md5=4c7958ad131ebbeeec7d4399bdeff12b (from https://pypi.python.org/simple/zipline/), version: 1.0.2
Found link https://pypi.python.org/packages/17/d3/8c58193ec8052d86ff67c00a285a01f646d3d53106844716090c22bba15e/zipline-0.6.0.tar.gz#md5=75d818c291df133946bb15a1b08ae0d8 (from https://pypi.python.org/simple/zipline/), version: 0.6.0
Found link https://pypi.python.org/packages/1f/8c/55ea3687c717bc532753860196222f12717201719625d043448ea94f4ff6/zipline-0.5.10.tar.gz#md5=48f394a5ea83848642d879cbeaba8342 (from https://pypi.python.org/simple/zipline/), version: 0.5.10
Found link https://pypi.python.org/packages/22/4a/affbfd183fa4133d13ecebc069bf9887c7755e531175384b57879daecfe2/zipline-0.8.3.tar.gz#md5=042ffcee614d2279add9a1bfd27a33cf (from …Run Code Online (Sandbox Code Playgroud) 我创建了一个帖子类型CPT UI:
add_action( 'init', 'cptui_register_my_cpts_matratze' );
function cptui_register_my_cpts_matratze() {
$labels = array(
"name" => __( 'Matratzen', '' ),
"singular_name" => __( 'Matratze', '' ),
);
$args = array(
"label" => __( 'Matratzen', '' ),
"labels" => $labels,
"description" => "",
"public" => true,
"publicly_queryable" => true,
"show_ui" => true,
"show_in_rest" => false,
"rest_base" => "",
"has_archive" => true,
"show_in_menu" => true,
"exclude_from_search" => false,
"capability_type" => "post",
"map_meta_cap" => true,
"hierarchical" => false,
"rewrite" => array( "slug" => …Run Code Online (Sandbox Code Playgroud) 我正在尝试使用passport-local的node_acl.当我运行我的代码时,我无法确保路由,并且我被重定向到页面.admin-user '/admin'/login
在下面找到我的最小runnable示例:
require('dotenv').config()
const express = require('express')
// const fs = require('fs')
const path = require('path')
const logger = require('morgan')
const bodyParser = require('body-parser')
const cookieParser = require('cookie-parser')
const session = require('express-session')
const passport = require('passport')
const LocalStrategy = require('passport-local').Strategy
const ACL = require('acl')
// load user.json file
// const d = fs.readFileSync(path.join(__dirname, '/../data/user.json'))
// const userObj = JSON.parse(d)
const userObj = [{
id: 1,
username: 'admin',
password: 'admin',
email: 'admin@admin.com',
role: 'admin',
}, …Run Code Online (Sandbox Code Playgroud) 我正在使用wordpress 4.9.7,我正在使用advanced custom fields 4.4.12.
在我的后端,我有一个被调用的帖子类型coins,它有一个叫做的关系字段related_coins和一个被调用的文本字段algorithm.基本上我的关系字段创建了与自定义帖子类型的关系products.所以产品可以与几个硬币有关系.
我目前只能按帖子类型过滤.但是,我想按algorithm帖子类型的自定义字段进行过滤coin.
我尝试了以下方法:
function graphic_card_products_query( $args, $field, $post_id ) {
$args['meta_query'] = array(
array(
'key' => 'algorithm', // name of custom field
'value' => 'related_coins',
'compare' => 'LIKE'
)
)
// return
return $args;
}
// filter for every field
add_filter('acf/fields/relationship/query/name=related_coins', 'graphic_card_products_query', 10, 3);
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基本上我试图得到自定义字段algorithm具有的所有值的列表,并将其作为过滤器选项返回到关系字段related_coin.
目前我什么都没收到.
有什么建议我做错了吗?
我正在使用"chai": "^4.2.0"和"mocha": "^6.1.4",。
当assert.equal()用于比较两个日期时,即使这两个日期似乎相同,我也会出错:
这是我的示例测试:
it('check if dates are correctly added', async () => {
let dataArr = [{'rating_date':'6/6/2019','impact_on_price':'Low'}]
let priceServ = new PriceService()
// clear all records
priceServ.clearPriceTable()
// add 1 record
const res = await priceServ.createOrUpdatePrice(dataArr)
// get "all" records from the table that have a certain action attribute
const tableValues = await priceServ.getPricesByField('rating_date')
assert.equal(tableValues[0].rating_date, new Date(dataArr[0].rating_date));
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});
任何建议我做错了什么?
我感谢您的回复!