小编JoT*_*aRo的帖子

Hello i've a table similar to this one:

id     sponsor     name
------------------------
1      0          Sasha
2      1          John
3      1          Walter
4      3          Ashley
5      1          Mark
6      4          Alexa       
7      3          Robert
8      3          Frank
9      4          Marika
10     5          Philip
11     9          Elizabeth

when i choose an ID (call it MYCHOICE) i want know all the name of people who has sponsor like MYCHOICE... is simply:

select * from tablename where sponsor=MYCHOICE

but... here is the problem... i …

您好,可以在矩形的中心创建一个倒圆角的三角形,就像在许多着陆页中一样.如下图所示:

我在这里找到了类似的东西,但没有倒圆角 CSS倒三角形图像叠加