小编non*_*one的帖子

考虑以下枚举类

public enum ClassA {
    CHECK1("X", 0),
    CHECK2("Y", 2),
    CHECK3("Z", 1);

    private final String id;
    private final String cdValue;

    private ClsA(String id, String cdValue) {
        this.id = id;
        this.cdValue = cdValue;
    }

    private String getId() {
        return id;
    }

    private String getCdValue() {
        return cdValue ;
    }

    private static final List<String> cdValues = new ArrayList<String>();

    static {
        for (ClassA clsA : ClassA.values()) {   
            cdValues.add(clsA.getCdValue());    
        }
    }   

    public boolean isCdValue(String cdValue)
    {
        if clsValues.contains(cdValue)
            return true;
        else return false;
    }   
} …

我们目前有两个客户代码"CUSTA"和"CUSTB".CUSTA可以执行操作A1,A2,A3,A4,A5,A6.CUSTB可以根据某些条件执行操作B1,B2,B3,B4,B5,B6.目前他们不再期待更多客户代码,但我希望设计灵活.这些可以存储在数据库中,但正如我所提到的,因为很长一段时间不可能有另一个客户代码,它需要用代码表示.

应用程序逻辑基本算法看起来像

if ConditionX is true
then if customerCode is "CUSTA"
     then  applicableOperation = 'A1'
     else
         if customerCode is "CUSTB"
         then applicableOperation = 'B1'
      end
else
     if ConditionY is true     
     then
         if customerCode is "CUSTA"
         then  applicableOperation = 'A2'
         else
             if customerCode is "CUSTB"
              then applicableOperation = 'B2'
          end
      else

............... .................

我可以编写switch语句等来清理算法,但主要关注的是如何表示"CUSTA","CUSTB","A1","A2","A3","A4"......"A6" , "B1", "B2" ... "B6".客户代码是否像枚举一样

public enum CustomerCode { CUSTA, CUSTB }
public enum OperationsForA{ A1, A2, A3,...A6 }
public enum OperationsForB{ B1, B2, B3...B6}

我应该创建一个Map …