TL; 博士
父组件如何知道其下每个子组件的渲染何时完成以及用户可见的 DOM 是最新版本?
假设我有一个由孙组件组成的component A子组件。这些孙组件中的每一个都从一个 RESTful API 端点获取数据,并在数据可用时呈现自身。Grid3x3
I would like to cover the entire area of Component A with a loader placeholder, to be unveiled only when the last of the components in the grid has fetched the data successfully, and rendered it, such that it's already on the DOM and can be viewed.
The user experience should be a super smooth transition from "loader" to a fully populated grid without flickering.
My …
我的PHP项目使用PGSQL.它在我的开发机器上从Homestead成功运行.一旦hhvm: true我在homestead.yaml和配置中添加我的项目 - 我的网络应用程序抛出PDOException一个驱动程序找不到.当我删除hhvm:true并重新提供宅基地时,例外情况就消失了.
显然HHVM的配置不包括PGSQL驱动程序.
我该如何纠正?
我想构建一个支持多种平台的应用程序:桌面应用程序(Mac/PC),Web(angularJS前端)和本机移动应用程序.
所以我在想一个应用服务器,为上面的平台提供内部API.关于如何支持登录/注销,我有一些假设.如果有人能评论我的想法是错的,我会很高兴.
这是一种常见的模式吗?
在我的小部件中,我可以做类似的事情:
MyWindow::MyWindow(QWidget *parent) :
QWidget(parent)
{
ui.setupUi(this);
setStyleSheet("QWidget { background-color: red }"); // <--- HERE
}
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这会将小部件背景设置为红色.
我的资源中有一个QSS文件.我如何指示我的小部件从那里获取其样式表内容,而不仅仅是将qss语法作为参数?
We're enabling our users to upload videos onto our S3 bucket. It's been fitted with the "acceleration" option and using Multi-Part upload from our JS. However, we've noticed something very disturbing: We have thousands of successful uploads from countries where the Internet is fast.
However, virtually all slow connection users (who all happen to be from places the internet isn't famous for speed) fail to upload. Once they do begin to upload they get dozens these errors on their console …
是#include <file>仅用于标题还是仅仅是机械"在此处注入此代码",可以在代码中的任何位置使用?
如果我在cpp函数中使用它来从单个源"注入"代码怎么办?这会有用吗还是编译器会为此尖叫?
在Mac OSX上运行QT Creator 2.4.
如何更改生成的最终.app文件的名称?它似乎与.Pro文件的名称绑定.
场景:
同样的浏览器
结果:Laravel 5在进入我的代码之前崩溃:
堆:
Symfony\Component\Debug\Exception\FatalErrorException Call to a member function setCookie() on null
vendor/laravel/framework/src/Illuminate/Session/Middleware/StartSession.php:184 __construct
vendor/laravel/framework/src/Illuminate/Foundation/Bootstrap/HandleExceptions.php:131 fatalExceptionFromError
vendor/laravel/framework/src/Illuminate/Foundation/Bootstrap/HandleExceptions.php:116 handleShutdown
vendor/laravel/framework/src/Illuminate/Foundation/Bootstrap/HandleExceptions.php:0 addCookieToResponse
vendor/laravel/framework/src/Illuminate/Session/Middleware/StartSession.php:72 handle
vendor/laravel/framework/src/Illuminate/Pipeline/Pipeline.php:125 Illuminate\Pipeline\{closure}
vendor/laravel/framework/src/Illuminate/Cookie/Middleware/AddQueuedCookiesToResponse.php:36 handle
vendor/laravel/framework/src/Illuminate/Pipeline/Pipeline.php:125 Illuminate\Pipeline\{closure}
vendor/laravel/framework/src/Illuminate/Cookie/Middleware/EncryptCookies.php:40 handle
vendor/laravel/framework/src/Illuminate/Pipeline/Pipeline.php:125 Illuminate\Pipeline\{closure}
vendor/laravel/framework/src/Illuminate/Foundation/Http/Middleware/CheckForMaintenanceMode.php:42 handle
vendor/laravel/framework/src/Illuminate/Pipeline/Pipeline.php:125 Illuminate\Pipeline\{closure}
vendor/laravel/framework/src/Illuminate/Pipeline/Pipeline.php:101 call_user_func:{/home/vagrant/dev/opus-web-app/vendor/laravel/framework/src/Illuminate/Pipeline/Pipeline.php:101}
vendor/laravel/framework/src/Illuminate/Pipeline/Pipeline.php:101 then
vendor/laravel/framework/src/Illuminate/Foundation/Http/Kernel.php:115 sendRequestThroughRouter
vendor/laravel/framework/src/Illuminate/Foundation/Http/Kernel.php:84 handle
public/index.php:53 {main}
public/index.php:0 [main]
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即使我从路由中删除了Route :: group(['middleware'=>'auth']组...在标签1中转到现在打开的URL会产生这个错误.我只是不明白.
我怎么摆脱这个?
我有这个 Vimeo 网址。
https://vimeo.com/192207770/0faf1dd09d
我不明白这两个 IDS 代表什么以及如何将其缩短为单个 ID URL。
我见过的所有其他 vimeo 网址都是vimeo.com/<id>
这两个IDS按这个顺序代表什么意思呢?我可以用来寻址的唯一视频 ID 在哪里vimeo.com/<id>?
这行在routes.php中有效:
Route::get('faq', 'HomeController@faq');
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所以我将其注释掉并尝试这样:当用户登录时不起作用.它不会重定向到上述代码中的控制器操作:
Route::get('faq', function()
{
if (Auth::check())
{
return redirect()->action('HomeController@faq');
}
else
{
return Redirect::to('/');
}
});
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错误:
New exception in xxxx.xx
InvalidArgumentException · GET /faq
Action App\Http\Controllers\HomeController@faq not defined.
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但控制器和方法显然在那里.显然我做错了什么.