下面的代码块一直在抛出错误.
Timeout after 20000ms of waiting for a connection.","stackTrace":[{"file":"BaseHikariPool.java","line":228,"className":"com.zaxxer.hikari.pool.BaseHikariPool","method":"getConnection"
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此外,我的数据库访问看起来太慢,xs.map()的每个元素大约需要1秒.下面,getFutureItem()调用db.run().
xs.map{ x =>
val item: Future[List[Sometype], List(Tables.myRow)] = getFutureItem(x)
Await.valueAfter(item, 100.seconds) match {
case Some(i) => i
case None => println("Timeout getting items after 100 seconds")
}
}
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Slick会在每次迭代"x"值时记录此信息:
[akka.actor.default-dispatcher-3] [akka://user/IO-HTTP/listener-0/24] Connection was PeerClosed, awaiting TcpConnection termination...
[akka.actor.default-dispatcher-3] [akka://user/IO-HTTP/listener-0/24] TcpConnection terminated, stopping
[akka.actor.default-dispatcher-3] [akka://system/IO-TCP/selectors/$a/0] New connection accepted
[akka.actor.default-dispatcher-7] [akka://user/IO-HTTP/listener-0/25] Dispatching POST request to http://localhost:8080/progress to handler Actor[akka://system/IO-TCP/selectors/$a/26#-934408297]
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我的配置:
"com.zaxxer" % "HikariCP" % "2.3.2"
default_db {
url = ...
user = …Run Code Online (Sandbox Code Playgroud) 我正在安装Sbt-Assembly,但现在卡住了.
Sbt Version (from 'sbt about'): 0.13.8
Current project is built against scala 2.11.6
Sbt, sbt plugins, and build definitions are using Scala 2.10.4
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addSbtPlugin("com.eed3si9n" % "sbt-assembly" % "0.14.0")
resolvers += Resolver.url("bintray-sbt-plugins", url("http://dl.bintray.com/sbt/sbt-plugin-releases"))(Resolver.ivyStylePatterns)
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scalaVersion in ThisBuild := "2.11.6"
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scalaVersion := "2.11.6"
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我意识到sbt-assembly是针对scala 2.10的.如果我将我的项目更改为scala 2.10,我有2.10的新不可用依赖项,这是不可取的.有没有办法配置我的项目只使用2.10组装插件?
==== bintray-sbt-plugins: tried
http://dl.bintray.com/sbt/sbt-plugin-releases/com.eed3si9n/sbt-assembly/scala_2.11/sbt_0.13/0.14.0/ivys/ivy.xml
::::::::::::::::::::::::::::::::::::::::::::::
:: UNRESOLVED DEPENDENCIES ::
::::::::::::::::::::::::::::::::::::::::::::::
:: com.eed3si9n#sbt-assembly;0.14.0: not found
::::::::::::::::::::::::::::::::::::::::::::::
Note: Some unresolved dependencies have extra attributes.
Check that these dependencies exist with the requested attributes.
com.eed3si9n:sbt-assembly:0.14.0 …Run Code Online (Sandbox Code Playgroud) 当StanfordNLP的TreeLSTM与具有> 30K实例的数据集一起使用时,会导致LuaJit错误地显示"Not Enough Memory".我正在使用LuaJit Data Structures解决这个问题.为了将数据集放在lua堆之外,需要将树放在LDS.Vector中.
由于LDS.Vector包含cdata,第一步是将Tree类型转换为cdata对象:
local ffi = require('ffi')
ffi.cdef([[
typedef struct CTree {
struct CTree* parent;
int num_children;
struct CTree* children [25];
int idx;
int gold_label;
int leaf_idx;
} CTree;
]])
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在read_data.lua中还需要进行一些小的更改来处理新的cdata CTree类型.到目前为止,使用LDS似乎是解决内存限制的合理方法; 但是,CTree需要一个名为"composer"的字段.
Composer的类型为nn.gModule.继续使用此解决方案将涉及将nn.gModule的typedef创建为cdata,包括为其成员创建typedef.在继续之前,这似乎是正确的方向吗?有没有人遇到过这个问题?
我试图找出下面代码的运行时间,如果列表是一个arraylist,如果它是一个链表.我很感激任何建议!
数组:我认为删除操作是O(n),循环是N/2,所以O(n ^ 2)
LinkedList:只有引用更改,因此删除的循环时间和循环的N/2,所以O(n)
int halfSize = lst.size() / 2;
for (int i = 0; i < halfSize; i++){
lst.remove(0);
}
Run Code Online (Sandbox Code Playgroud) 我正在使用 slick 3.0.0-M1 和 "com.zaxxer" % "HikariCP" % "2.4.3"
Slick 正在为每个查询(由日志记录表明)准备一条语句,这是不好的:
"Preparing statement: select * from ..."
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我的配置告诉 Slick / Hikari 缓存准备好的语句:
myDB {
url = "jdbc:mysql://...
user = ...
...
connectionPool = HikariCP
queueSize = 50000
maxConnections = 50
properties.cachePrepStmts = true
properties.prepStmtCacheSize = 20000
properties.prepStmtCacheSqlLimit = 100000
}
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日志似乎表明这些属性已被读取:
configuration:
...
dataSourceName..................
dataSourceClassName.............
dataSourceProperties............
{password=<masked>,
prepStmtCacheSqlLimit=100000,
cachePrepStmts=true,
prepStmtCacheSize=20000}
maximumPoolSize.................50
poolName..........................
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db 对象被实例化并在测试中使用:
val db = Database.forConfig("", config.getConfig("myDB"))
val qTemplate = StaticQuery[(Int), MyRow] + "select * from table_name where …Run Code Online (Sandbox Code Playgroud) 现在,我的函数使用 argmax:
p = tf.stop_gradient(tf.argmax(prev, 1))
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我曾尝试使用以下方法,但 dimn 不兼容:
p = tf.stop_gradient(tf.nn.top_k(prev, 2)[1])
raise ValueError("Linear is expecting 2D arguments: %s" % str(shapes))
ValueError: Linear is expecting 2D arguments: [[None, 2, 1024], [None, 1024]]
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我的 TF 版本可能是 0.5,这就是 top_k 只有 2 个参数的原因。
我有一个演员,打算做一个长期运行的工作,不再收到任何消息:
actor {
def receieve => longRunningJob()
}
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如何调试这个演员的杀戮?
我按照文档说"在一个actor中,你可以通过使用上下文引用来阻止一个子actor:"
context.stop(childActor)
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我还尝试向孩子发送Kill消息,Stop消息和PoisonPill消息,但是在长时间运行的作业中间没有任何阻止它.
I am trying to convert binary to decimal in the MIPS language, using the MARS simulator. The program accepts a binary number, and then does the conversion, by multiplying (shift left by the number's place $t9). Another way of saying that is multiplying each 1 digit by 2 raised to the power of the place, and summing that result.
I do not have a very good understanding of how values are stored and communicated between ascii, decimal, and the problem …
我收到此编译错误:
[warn] ::::::::::::::::::::::::::::::::::::::::::::::
[warn] :: UNRESOLVED DEPENDENCIES ::
[warn] ::::::::::::::::::::::::::::::::::::::::::::::
[warn] :: com.typesafe.sbt#sbt-scalariform;1.3.0: not found
[warn] ::::::::::::::::::::::::::::::::::::::::::::::
[warn]
[warn] Note: Some unresolved dependencies have extra attributes. Check that these dependencies exist with the requested attributes.
[warn] com.typesafe.sbt:sbt-scalariform:1.3.0 (scalaVersion=2.11, sbtVersion=0.13)
[warn]
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在我的项目的根目录中,我有一个build.sbt文件:
scalaVersion in ThisBuild := "2.11.6"
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我还有一个core/build.sbt文件,其中包含多个解析器,libraryDependencies和排除项.
project/plugins.sbt:
addSbtPlugin(...)
resolvers += "Typesafe Public Repo" at "http://repo.typesafe.com/typesafe/releases"
resolvers += "JBoss Repository" at "http://repository.jboss.org/nexus/content/groups/public//"
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〜/名.bst/0.13/global.sbt
scalaVersion := "2.11.6"
Run Code Online (Sandbox Code Playgroud) 我得到一个段.当我尝试从char类型中减去32时(尝试在C中转换为小写而没有tolower())我已经完成了错误.我已经完成了前提条件搜索相关的Q/A线程而没有运气.我也试过'a' - 'A'对于转换值,'32',将其转换为(char*)以及我能想到的任何其他内容.例如:
char* s1 = "Bob";
if (*s1 >= 97 && *s1 <= 122)
*s1 -= 32;
}
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有什么建议?
编辑:
在按照下面的帮助后,我仍然得到错误.(对于此示例,我只是尝试将名称的第一个字母更改为小写.)以下是我正在尝试的内容:
char* s1 = "Bob";
printf("\n %s before", s1);
// below I call my string length function to get actual size instead of 100
char* temp = malloc(100);
temp = s1;
if (*temp >= 'A' && *temp <= 'Z'){
*temp -= 32;
}
printf("\n%s after", temp);
free(temp);
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另外,为什么我需要为已经在内存中的字符串分配内存?